The area of a rhombus is 1/2 times the lengths of the diagonals
A = (1/2)(AC)(BD)
Since the diagonals bisect each other, and ed = 8, BD must be 16. Substituting in this for BD and the given area (168) we get the following:
168 = (1/2)(AC)16
168 = 8(AC)
21 = AC
Answer:
(0.91)^{20}(0.09)
Step-by-step explanation:
Answer:
291.666666667
Step-by-step explanation:
one minute is 60 seconds
17500 divided by 60
291.666666667
Answer:
Step-by-step explanation:
1. here you go mate
step 1
6x - 12 < 6 equation
step 2
6x - 12 < 6 simplify
6x-12+12<6+12
step 3
6x<18 Divide both sides

answer
x<3
2. Here you go mate
step 1
2(3x-8) >8 equation
step 2
2(3x-8) >8 simplify
6x-16+16>8+16
step 3
6x>24 divide both sides

answer
x>4
false; Dan may be enrolled in a different zero-hour class