Answer:
C. 9
Step-by-step explanation:
Please let me know if you want me to add an explanation as to why this is the answer. I can definitely do that, I just wouldn’t want to write it if you don’t want me to :)
Answer:
Step-by-step explanation:
Suppose the dimensions of the playground are x and y.
The total amount of the fence used is given and it is 780 ft. In terms of x and y this would be 3x+2y=780 (we add 3x because we want it to be cut in the middle). Therefore, y= 780/2-3/2x. Now, the total area (A )to be fenced is
A=x*y= x*(390-3/2x)=-3/2 x^2+390x
Calculating the derivative of A and setting it equals to 0 to find the maximum
A'= -3x+390=0
This yields x=130.
Therefore y=780/2-3/2*130=195
Thus, the maximum area is 130*195=25,350ft^2
Answer:
y=2x+3
Step-by-step explanation:
in third line x = 0 y=2×0+3 =3
Answer:16.110
Step-by-step explanation:
Answer:
a) K3050 and b) K1150
Step-by-step explanation:
a) Add all his expenditures
i.e: K300+K150+K100
=K3050
b) Subtract the remaining of his spendings from the total
i.e: K4209 - K3050
=K1150
