There are 8 divisions on this number line between 0.08 and 0.40, so the width of each div. is 0.32/8, or 0.04.
Starting with 0.08, fill in the boxes as follows: 0.12, 0.16, 0.20, .... 0.28, 0.32, 0.63, ... , and 0.44.
Answer:
JUST USE THE CALCULATOR DUHHH!!!
Perimeter of bigger disc = 2π*24 inch
perimeter of bigger disc = 2π*8 inch
number of rotations =2π*24/2π*8 = 3
Answer:
2097150
Step-by-step explanation:
<u>GIVEN :-</u>
- First term of G.P. = 6
- Forth term of G.P. = 384
<u>TO FIND :-</u>
- Sum of first 10 terms of the G.P.
<u>CONCEPT TO BE USED IN THIS QUESTION :-</u>
<em>Geometric Progression :-</em>
- It's a sequence in which the successive terms have same ratio.
- General form of a G.P. ⇒ a , ar , ar² , ar³ , ....... [where a = first term ; r = common ratio between successive terms]
- Sum of 'n' terms of a G.P. ⇒
.
<em>[NOTE :- </em>
can also be the<em> formula for "Sum of n terms of G.P." because if you put 'r' there (assuming r > 0) you'll get negative value in both the numerator & denominator from which the negative sign will get cancelled from the numerator & denominator. </em><em>YOU'LL BE GETTING THE SAME VALUE FROM BOTH THE FORMULAES.</em><em>]</em>
<u>SOLUTION :-</u>
Let the first term of the G.P. given in the question be 'a' and the common ratio between successive terms be 'r'.
⇒ a = 6
It's given that <u>forth term</u> is 384. So from "General form of G.P." , it can be stated that :-


Divide both the sides by 6.


![=> r = \sqrt[3]{64} = 4](https://tex.z-dn.net/?f=%3D%3E%20r%20%3D%20%5Csqrt%5B3%5D%7B64%7D%20%3D%204)
Sum of first 10 terms 



(1) Answer: (D) Cubic (the highest power of x is 3)
(2) Answer: (C) Quadratic (power of x is 2)
(3) Answer: (B) Linear (highest degree 1)
(4) Answer: (A) Constant (the quadratic terms cancel out, constant left)