So i'm assuming 33^a is saying any number that is a square of 33 inside of 1,313 so first, to find how many even numbers divide 1,313 by two to get 656.5 so if I am not mistaken 656 numbers in 1,313 will be even. Now find all squares of 33 that don't pass 1,313 which is 33 itself and 1,089 because 33^3 is 35,937 so add 2 to 656 to get 668. so the probability is 658/1,313 i believe.
The center is (-1, -2) and the radius of the circle is 5.
<h3>What is the equation of a circle?</h3>
The circle equation formula refers to the equation of a circle which represents the center-radius form of the circle.
A circle can be represented as;
Where; h and k are the center of the circle r is the radius of the circle.
The given equation of the circle is;
Comparing both the equations;
Hence, the center is (-1, -2) and the radius of the circle is 5.
Learn more about circle here;
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Answer:
7/3
Step-by-step explanation:
i hope this works :)
Answer:
The best point of estimate for the true mean is:
Since the time can't be negative a good approximation for the confidence interval would be (0,5.248) minutes. The interval are tellling to us that at 95% of confidence the average late time is lower than 5.248 minutes.
Step-by-step explanation:
Information given
represent the sample mean for the late time for a flight
population mean
represent the population deviation
n=76 represent the sample size
Confidence interval
The best point of estimate for the true mean is:
The confidence interval for the true mean is given by:
(1)
The Confidence level given is 0.95 or 95%, th significance would be and . If we look in the normal distribution a quantile that accumulates 0.025 of the area on each tail we got
Replacing we got:
Since the time can't be negative a good approximation for the confidence interval would be (0,5.248) minutes. The interval are tellling to us that at 95% of confidence the average late time is lower than 5.248 minutes.
Answer:
0.5372
Step-by-step explanation:
Given that the number of births that occur in a hospital can be assumed to have a Poisson distribution with parameter = the average birth rate of 1.8 births per hour.
Let X be the no of births in the hospital per hour
X is Poisson
with mean = 1.8
the probability of observing at least two births in a given hour at the hospital
=
the probability of observing at least two births in a given hour at the hospital = 0.5372