Given : A scientist conducted an experiment. Due to chemical reaction, the temperature of a compound rose $\frac{1}{10}$ degree every $\frac{1}{4}$ hour for a limited time.

To find : What was the rate, in degrees per hour that the temperature of the compound rose ?

Solution :

In every $\frac{1}{4}$ hour the temperature of a compound rose $\frac{1}{10}$ degree

To get the rate, in degrees per hour,

In every 1 hour the temperature of a compound rose is

$r=\dfrac{\frac{1}{10}}{\frac{1}{4}}$ degree

$r=\dfrac{4}{10}$ degree/hr

$r=\dfrac{2}{5}$ degree/hr

Therefore, the rate is $\frac{2}{5}$ degree per hour.

5 0

2 years ago

Solve and reduce to lowest terms:<br> 6 / 11 x 1 / 3

zysi [14]

Answer:

2/11

Step-by-step explanation:

6/11 x 1/3 =

6/33 =

2/11

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

5 0

3 years ago

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Use substitution to solve the problem below algebraically.<br><br> x = 41<br> x + 2y = 71

grandymaker [24]

Answer:

41 + 2y = 71

2y = 30

y = 15

Step-by-step explanation:

i believe that is right, if not sorry

7 0

2 years ago

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