Answer:
B
Step-by-step explanation:
Data set D does not contain the value 128, which is the median value.
Data set C does not contain the outlier value 91.
Data set A contains value 168, which does not show up on the plot.
The only remaining choice is B.
_____
In order, the data values of set B are ...
... 91, 114, 120, 126, 128, 128 134, 136, 139, 142, 152
The median value of these 11 is the 6th one: 128. The median values of the remaining two sets of 5 are 120 and 139, making these values the quartiles at the ends of the box. The value 91 is more than 1.5 times the IQR (19) below the 1st quartile, so is considered an outlier. (The cutoff is 120-1.5·19=91.5.)
Answer:
93. Divide 248 by 8. One eighth of 248 = 31.
June sold 3/8 of the 248 oranges.
If 1/8 = 31 and June sold 3/8 of the oranges.
Multiply 3 × 31. Therefore June sold 93 oranges.
Step-by-step explanation:
Hey there!
If the price per orange is $.26 and we want to know how many oranges he bought and we have our total, we can set o equal to how many oranges he got and set up an algebraic equation:
0.26o = 2.08
We multiply .26 by o because o is how many oranges he bought and that's what we're solving for- so we multiply by the unit price.
To isolate o, we divide both sides by .26 to get:
The answer is C- Jim bought 8 oranges.
Hope this helps!
Answer:
tyson had the better deal.
Step-by-step explanation:
hed had the better deal because 168 divided by 8 is 21 which is less than 24
