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amid [387]
3 years ago
10

There are 7 girls on a bus. each girl has 7 backpacks. each backpack has 7 big cats. each big cat has 7 little cats. how many le

gs are on the bus?
Mathematics
2 answers:
melamori03 [73]3 years ago
7 0
There are seven girls and each girl has seven backpacks so to find the number of backpacks you would multiply 7x7 which equals 49 backpacks on the bus. Each backpack had 7 big cats so to find the number of big cats you would multiply 49x7 which equals 343 big cats. the big cats have 7 little cats so to find the number of little cats you would multiply 343x7 which equals 2401 little cats. Add the number of big cats and little cats. That would be 2744 cats in total. I am going to assume that none of the cats have injuries or deformities so they would all have 4 legs. To find the number of legs in the bus you would multiply the number of cats by 4.
Vera_Pavlovna [14]3 years ago
6 0
7 girls on a bus, each has two legs. 7 * 2 = 14. 

Each girl has 7 backpacks. So 7 * 7 = 49. 

49 * 7 = 343 cats in total 

343 * 4 = 1,372 cat legs. 

343 * 7 = 2401 small cats 

2401 * 4 = 9,604 cat legs 

14 + 1,372 + 2,401, + 9,604 = 10,990 legs in total
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3 years ago
Does the frequency distribution appear to have a normal​ distribution? Explain. Temperature ​(degrees​F) Frequency 35 dash 39 1
AlexFokin [52]

Answer:

D. ​Yes, because the frequencies start​ low, proceed to one or two high​ frequencies, then decrease to a low​ frequency, and the distribution is approximately symmetric.

Step-by-step explanation:

Hello!

The given frequency distribution for temperatures.

To see if the distribution appears to have a normal distribution you have to draw a histogram using the information. Check attachment.

As you can see, the distribution appears symmetric, it starts low and proceeds to grow until it reaches its maximum point (f(4)=13) and then starts to decrease to low frequencies. The right tail decreases a little more than the left one but it is almost symmetrical.

I hope this helps!

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3 years ago
Jefferson High School has a student body of 6⁴ students. Each class has approximately 6² students. How many classes does the sch
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7 0
3 years ago
HELPPPP JUST 2 QUESTIONS BASED ON PYTHAGOREAN THEOREM AND IM CONFUSED HELPPPP​
Anna007 [38]

9514 1404 393

Answer:

  3. no; does not have the correct ratio to other sides

  4. (1; right), (2; obtuse), (3; right)

Step-by-step explanation:

3. There are a couple of ways you can go at this.

a) the ratio of sides of a 30°-60°-90° right triangle (half an equilateral triangle) is 1 : √3 : 2. Here, the ratio of sides is ...

  (√30/2) : √15 : √30 = 1 : √2 : 2 . . . . MQ is <em>not</em> the height

b) the height is perpendicular to the base, so if MQ were the height, the sides of the triangle would satisfy the Pythagorean theorem:

  LQ² +MQ² = LM²

  (√30/2)² +(√15)² = (√30)²

  30/4 +15 = 30

  22.5 = 30 . . . . NOT TRUE

The length MQ cannot be the height of ∆LMN. (It is too short.)

__

4. To see if these lengths form a right triangle, you can test them in the Pythagorean theorem relation. In the attached we have reformulated the equation so it gives a value of 0 if the triangle is a right triangle:

  c² = a² +b² . . . . . Pythagorean theorem

  c² -a² -b² = 0 . . . . rewritten

If the value of c² -a² -b² is not zero, then the side lengths do not form a right triangle. The attached shows this math performed by a graphing calculator. The results are ...

  1. right triangle
  2. not a right triangle — long side is too long, so the triangle is obtuse
  3. right triangle

_____

<em>Additional comment</em>

The attached table demonstrates an artifact of computer arithmetic. Not all numbers can be represented exactly in a computer, so a difference that is expected to be zero using exact arithmetic may be slightly different from zero when computed by a computer or calculator. Here, we see a difference of about 6×10^-14 when zero is expected. On most calculators (with 10, or 12 displayed digits), this would be displayed as 0.

The same calculation done "by hand" gives ...

  (√425)² -5² -20² = 425 -25 -400 = 0 . . . Triangle 1 is a <em>right triangle</em>

4 0
3 years ago
In a recent​ poll, 44​% of survey respondents said​ that, if they only had one​ child, they would prefer the child to be a boy.
viva [34]

Answer:

a) The probability that 71 of 150 will prefer boy child is 71/150 or 0.47

b) The result contradicts the poll actual percentage is 47.33% which is 3.33% more than the poll predicted

Step-by-step explanation:

If 71 out of 150 prefer boy child

The probability that the 71 will prefer boy child is

= 71/150

The actual percentage is

(71/150)*100%

= 47.33%

This contradicts the poll as this is more than the poll predicted. That means Less than 71 of 150 actually preferred boy child.

5 0
4 years ago
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