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amid [387]
2 years ago
10

There are 7 girls on a bus. each girl has 7 backpacks. each backpack has 7 big cats. each big cat has 7 little cats. how many le

gs are on the bus?
Mathematics
2 answers:
melamori03 [73]2 years ago
7 0
There are seven girls and each girl has seven backpacks so to find the number of backpacks you would multiply 7x7 which equals 49 backpacks on the bus. Each backpack had 7 big cats so to find the number of big cats you would multiply 49x7 which equals 343 big cats. the big cats have 7 little cats so to find the number of little cats you would multiply 343x7 which equals 2401 little cats. Add the number of big cats and little cats. That would be 2744 cats in total. I am going to assume that none of the cats have injuries or deformities so they would all have 4 legs. To find the number of legs in the bus you would multiply the number of cats by 4.
Vera_Pavlovna [14]2 years ago
6 0
7 girls on a bus, each has two legs. 7 * 2 = 14. 

Each girl has 7 backpacks. So 7 * 7 = 49. 

49 * 7 = 343 cats in total 

343 * 4 = 1,372 cat legs. 

343 * 7 = 2401 small cats 

2401 * 4 = 9,604 cat legs 

14 + 1,372 + 2,401, + 9,604 = 10,990 legs in total
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The attendance at a seminar in year 1 was 500. In year 2, the attendance changed by 100. What was the percent change in attendan
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20%

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2 years ago
On Friday a local hamburger shop sold a combined total of 564 hamburgers and cheeseburgers. The number of cheeseburgers sold was
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Answer:

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Step-by-step explanation:

If there was a total of 564 and the cheeseburgers was three times the amount, you need to divide 564 by 3. 564 divided by 3 equals to 188. I am pretty sure this could be the correct answer!

3 0
2 years ago
Read 2 more answers
Two runners one averaging 5 miles per hour and the other one averaging 4 miles per hour, start at the same place and run along t
Vikentia [17]

Answer:

The Distance cover by both the Runners is same = 10 miles  

Step-by-step explanation:

According to question ,

The Speed of first runners (S 1) = 5 miles per hour

The speed of second runners (S 2)  = 4 miles per hour

Let The Time taken by First runner (T 1 ) = T hour

But the second runner  arrives half hour after the first runner ,

I.e The Time taken by Second runner (T 2) = ( T + \frac{1}{2} )

Now from Distance = Speed × Time

Since both the runners start from same place and run along the same trail

SO ,Both the Distance cover by both are same , D 1 = D 2

i.e Speed 1 × Time 1 = Speed 2 × Time 2

    5 mph × T            =  4 mph   ×  ( T + \frac{1}{2} )

    5 T =  4 T + ( 4 × \frac{1}{2} )

Or,  5 T - 4 T = 2

∴       T    =  2 hour  ,

Time take by first = T1 = T = 2 hour

Time take by second = T2 = T + \frac{1}{2} = (2  +  \frac{1}{2} )hour = \frac{5}{2}

Now the Distance cover = Speed × Time

              Distance   (D1)          = 5 mph  × 2 hour = 10 mile

And        Distance    (D2)         =  4 mph  × \frac{5}{2} = 10 miles

Hence, As The Distance cover by both the Runners is same = 10 miles  Answer

5 0
3 years ago
Solve the system. <br> x+3y=1 <br> -2x+7=-23
Viefleur [7K]
X+ 3y = 1  -----(first equation)
-2x+7 = -23 ---(second equation)
-2x = -23-7
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Now, Substitute the value of x in first equation,
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y = -14/3

In short, Final Answers are: x = 15 & y = -14/3

Hope this helps!
5 0
2 years ago
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