Ok so first you would write out the problem and on the side multiply six times 10 until you can't get 60 out of your number any more then you find out how many times 6 goes into the remainder and up the amount of times 6 went into 258 and whet ever is left over is your remainder
Answer:
approx. 251 in³
Step-by-step explanation:
The appropriate formula to use here is V = πr²h. Substituting 2 in for r and 5 in for h, we get:
V = π(2 in)^2·(5 in), or
V = π(4 in²)(5 in) = 80π in³, or approx. 251 in³
I agreed Angle 4 and 12 is the right answer
I really hope this helped you out
Nth term of gp = a(1 - r^n)/(1 - r), where n∞ = 10, n = ∞, a = 2, r < 1
10 = 2(1 - r^∞)/(1 - r)
10 = 2/(1 - r)
1 - r = 2/10 = 1/5
r = 1 - 1/5 = 4/5
An infinite deometric series with a beginning value of 2 that converges to 10 has common ratio of 4/5.
The first four terms are: 2, 1.6, 1.28, 1.024