Question

Jason is pulling a box across the room. He is pulling with a force of 10 newtons and his arm is making a 74 angle with the horizontal, what is the vertical component of the force he is pulling with?

Answer 1

Using vector concepts, it is found that the vertical component of the force is of 9.613 newtons.

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• A vector (x,y) has horizontal component x and vertical component y.
• The magnitude is $M = \sqrt{x^2 + y^2}$
• The components can be represented as function of the magnitude M and the angle between them $\alpha$, that is, $(M\cos{\alpha}, M\sin{\alpha}$

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• The force is of 10 newtons, that is, M = 10.
• Angle of 74 degrees, that is, $\alpha = 74$.
• The vertical component is y, thus:

$y = M\sin{\alpha} = 10\sin{74} = 9.613$

The vertical component of the force is of 9.613 newtons.

A similar problem is given at brainly.com/question/24606756

Answer 2

The vertical component of the force Jason is pulling with is 9.613 N.

The vertical component of a force is given as :

$F_{y} = Fsin\theta$

Force, F = 10 N

θ = 74°

Therefore,

$F_{y} = 10 \times sin74$

$F_{y} = 10 \times 0.9612616$

$F_{y} = 9.612 N$

Therefore, the vertical component of the force is 9.613 N

Learn more : brainly.com/question/1454477?referrer=searchResults