If a herd of deer lives in a forest where they eat the leaves of trees, then the amount of carbon in the trees and in the deer increases.
<h3>What is the matter cycle?</h3>
Matter cycling refers to the movement of matter (in this case carbon) from biotic and abiotic factors in an ecosystem.
The biotic components are living organisms, whereas abiotic components are the non-living part of the ecosystem.
The carbon is continuously cycling between living and non-living components in an ecosystem.
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Answer:
a. alphabet line
Explanation:
Technical drawings are the drawings that help in communicating the designs. These designs are the designs that provide the instruction for the manufacturing of any object. The designs are made with the help of lines and line symbols. Line symbols are termed to be alphabet of lines. They help the designers to draw the designs with accuracy. Various lines are drawn that differ in terms of thickness and darkness. These variations helps the designers to mark the design accurately.
Diane Sweeney student centered coaching is known to be a tool that is made a Results Based Coaching Tool which a person can use to in a coaching cycle.
<h3>What is the coaching tool about?</h3>
This tool is known to be one that is often used to put down the impact of teacher and student learning in all of a coaching cycle.
What are the Core Practices that is made for Student Centered Coaching; They include:
1. A person Setting goals that are meant for coaching cycles.
2. The use of a given standards-based learning targets.
3. The use of student evidence in the act of co-plan instruction.
4. The act of Organizing coaching in cycles.
6. Measuring the influence of coaching.
Note that it was made to Improve student outcomes in regards to data-driven coaching and it is said to be a kind of Student-Centered Coaching made on the fact that school-based coaching can be set up to directly influence student learning.
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The distance between the campsite and the rest area is 9 miles.
The given parameters:
- <em>Initial speed of the campers, u = 4.5 mph</em>
- <em>Final speed of the campers, v = 4 mph</em>
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Let the time of motion from the campsite to rest area = t (hours)
Time for return trip = t hours + 15 mins
= (t + 0.25) hours
Let the distance between the campsite and rest area = d
d = 4.5t
d = 4(t + 0.25)
4.5t = 4(t + 0.25)
4.5t = 4t + 1
4.5t - 4t = 1
0.5t = 1
t = 2 hours
The distance between the campsite and the rest area is calculated as follows;
d = 4.5t
d = 4.5 x 2
d = 9 miles
Thus, the distance between the campsite and the rest area is 9 miles.
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