Ask question

Ask question

All categories

3 years ago

8

Solve the inequality a + 18 < 7

1 answer:

Alexxandr [17]3 years ago

3 0

Answer:

a < - 11

Step-by-step explanation:

a + 18 < 7

a < 7 - 18

a < - 11

You might be interested in

People go to a carnival. Children tickets cost $4.50 and adult tickets cost $7.25. If they bought 28 tickets and spent $59, how

xenn [34]

Answer:

l

Step-by-step explanation:

l

4 0

3 years ago

Here I need help on all of these if you can help that would be amazing!! It’s 27 points pls help!

maria [59]

Answer:

umm sorry but i think you can do it im sure your smart go for it!

Step-by-step explanation:

3 0

3 years ago

What the square of 8^2

Novosadov [1.4K]

Answer:

8^2 = 64

unless you mean 8^2's square root then it is 8

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

What digit is in the ones place of the 357th even number?

wlad13 [49]

(357) the 3 is in the hundredth place, the 5 is in the tens place and the 7 is in the ones place

8 0

4 years ago

Match each spherical volume to the largest cross sectional area of that sphere

zlopas [31]

Answer:

Part 1) $324\pi\ units^{2}$ ------> $7,776\pi\ units^{3}$

Part 2) $36\pi\ units^{2}$ ------> $288\pi\ units^{3}$

Part 3) $81\pi\ units^{2}$ ------> $972\pi\ units^{3}$

Part 4) $144\pi\ units^{2}$ ------> $2,304\pi\ units^{3}$

Step-by-step explanation:

we know that

The largest cross sectional area of that sphere is equal to the area of a circle with the same radius of the sphere

Part 1) we have

$A=324\pi\ units^{2}$

The area of the circle is equal to

$A=\pi r^{2}$

so

$324\pi=\pi r^{2}$

Solve for r

$r^{2}=324$

$r=18\ units$

Find the volume of the sphere

The volume of the sphere is

$V=\frac{4}{3}\pi r^{3}$

For $r=18\ units$

substitute

$V=\frac{4}{3}\pi (18)^{3}$

$V=7,776\pi\ units^{3}$

Part 2) we have

$A=36\pi\ units^{2}$

The area of the circle is equal to

$A=\pi r^{2}$

so

$36\pi=\pi r^{2}$

Solve for r

$r^{2}=36$

$r=6\ units$

Find the volume of the sphere

The volume of the sphere is

$V=\frac{4}{3}\pi r^{3}$

For $r=6\ units$

substitute

$V=\frac{4}{3}\pi (6)^{3}$

$V=288\pi\ units^{3}$

Part 3) we have

$A=81\pi\ units^{2}$

The area of the circle is equal to

$A=\pi r^{2}$

so

$81\pi=\pi r^{2}$

Solve for r

$r^{2}=81$

$r=9\ units$

Find the volume of the sphere

The volume of the sphere is

$V=\frac{4}{3}\pi r^{3}$

For $r=9\ units$

substitute

$V=\frac{4}{3}\pi (9)^{3}$

$V=972\pi\ units^{3}$

Part 4) we have

$A=144\pi\ units^{2}$

The area of the circle is equal to

$A=\pi r^{2}$

so

$144\pi=\pi r^{2}$

Solve for r

$r^{2}=144$

$r=12\ units$

Find the volume of the sphere

The volume of the sphere is

$V=\frac{4}{3}\pi r^{3}$

For $r=12\ units$

substitute

$V=\frac{4}{3}\pi (12)^{3}$

$V=2,304\pi\ units^{3}$

5 0

3 years ago

Read 2 more answers