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Digiron [165]
2 years ago
6

Can someone actually help me with these problems? They are due tomorrow.

Mathematics
1 answer:
Ainat [17]2 years ago
3 0

Answer:

Hope this helps you

Step-by-step explanation:

43. A "Square" cornfield, which means all 4 sides has the same lenght BxH

164.000 ft^2=404.96 NO

156.816 ft^2=396 Yes

174724 ft^2=418 Yes

215908  ft^2=464.66 NO

44. it's the same here, if the area is 81. then each side of the square is 9

1st figure: it has 12 sides x9 =108

2nd figure: it has 10 sides x9=90

3rd figure: has also 12 sides x9=108

45. 13^3= 13x13x13 = 2197

46. 25^2= 25x25 = 625

47.  15^3= 15x15x15 = 3375

48. 34^2= 34x34 = 1156

49.  5 root121= 5 (11)=55

50. -6.root36= - 6 (6)= -36

51.  10 root3 (8) = 10(2) = 20

52. -4. root 144= -4(12) = -48

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Select the answer from each drop down menu. In tye diagram
maria [59]

Answer:

Theres no diagram or drop down menu

lmk when you get it and i will help you

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Can you please help me find the area? Thank you. :)))
Phoenix [80]

The figure shown in the picture is a rectangular shape that is missing a triangular piece. To determine the area of the figure you have to determine the area of the rectangle and the area of the triangular piece, then you have to subtract the area of the triangle from the area of the rectangle.

The rectangular shape has a width of 12 inches and a length of 20 inches. The area of the rectangle is equal to the multiplication of the width (w) and the length (l), following the formula:

A=w\cdot l

For our rectangle w=12 in and l=20 in, the area is:

\begin{gathered} A_{\text{rectangle}}=12\cdot20 \\ A_{\text{rectangle}}=240in^2 \end{gathered}

The triangular piece has a height of 6in and its base has a length unknown. Before calculating the area of the triangle, you have to determine the length of the base, which I marked with an "x" in the sketch above.

The length of the rectangle is 20 inches, the triangular piece divides this length into three segments, two of which measure 8 inches and the third one is of unknown length.

You can determine the value of x as follows:

\begin{gathered} 20=8+8+x \\ 20=16+x \\ 20-16=x \\ 4=x \end{gathered}

x=4 in → this means that the base of the triangle is 4in long.

The area of the triangle is equal to half the product of the base by the height, following the formula:

A=\frac{b\cdot h}{2}

For our triangle, the base is b=4in and the height is h=6in, then the area is:

\begin{gathered} A_{\text{triangle}}=\frac{4\cdot6}{2} \\ A_{\text{triangle}}=\frac{24}{2} \\ A_{\text{triangle}}=12in^2 \end{gathered}

Finally, to determine the area of the shape you have to subtract the area of the triangle from the area of the rectangle:

\begin{gathered} A_{\text{total}}=A_{\text{rectangle}}-A_{\text{triangle}} \\ A_{\text{total}}=240-12 \\ A_{\text{total}}=228in^2 \end{gathered}

The area of the figure is 228in²

8 0
1 year ago
Which expression can be expanded using the binomial theorem?
kirill [66]

Answer:

The third choice:  (x² - 1)³

Step-by-step explanation:

That is the only expression that is a binomial.  Binomial means "two numbers".  For this expression, x² is one number, and -1 is the other.  Choice 1 is a monomial (one number) and choices 2 and 4 are trinomials (three numbers)

7 0
3 years ago
Suppose a jar contains 8 red marbles and 14 blue marbles. If you reach in the jar and pull out 2 marbles at random, find the pro
NikAS [45]

it would most likely be blue because its more

it would be a  57.1429%. of blue

8 0
2 years ago
The position of an object moving along an x axis is given by x = 3.24 t - 4.20 t2 + 1.07 t3, where x is in meters and t in secon
Pavel [41]

Answer and explanation:

Given : The position of an object moving along an x axis is given by x=3.24t-4.20t^2+1.07t^3 where x is in meters and t in seconds.

To find : The position of the object at the following values of t :

a) At t= 1 s

x(t)=3.24t-4.20t^2+1.07t^3

x(1)=3.24(1)-4.20(1)^2+1.07(1)^3

x(1)=3.24-4.20+1.07

x(1)=0.11

b) At t= 2 s

x(t)=3.24t-4.20t^2+1.07t^3

x(2)=3.24(2)-4.20(2)^2+1.07(2)^3

x(2)=6.48-16.8+8.56

x(2)=-1.76

c) At t= 3 s

x(t)=3.24t-4.20t^2+1.07t^3

x(3)=3.24(3)-4.20(3)^2+1.07(3)^3

x(3)=9.72-37.8+28.89

x(3)=0.81

d) At t= 4 s

x(t)=3.24t-4.20t^2+1.07t^3

x(4)=3.24(4)-4.20(4)^2+1.07(4)^3

x(4)=12.96-67.2+68.48

x(4)=14.24

(e) What is the object's displacement between t = 0 and t = 4 s?

At t=0, x(0)=0

At t=4, x(4)=14.24

The displacement is given by,

\triangle x=x(4)-x(0)

\triangle x=14.24-0

\triangle x=14.24

(f) What is its average velocity from t = 2 s to t = 4 s?

At t=2, x(2)=-1.76

At t=4, x(4)=14.24

The average velocity  is given by,

\triangle x=x(4)-x(2)

\triangle x=14.24-(-1.76)

\triangle x=14.24+1.76

\triangle x=16

4 0
3 years ago
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