Question

Triangle ABC has vertices A(3,0),

Answer 1

Solving for the Distance between two Points

Answer:

$4\sqrt{5}$

Step-by-step explanation:

If you have the two points, $(x_1,y_1)$ and $(x_2,y_2)$, the distance, $d$, between them can be calculated by $d = \sqrt{(x_2 -x_1)^2 +(y_2 -y_1)^2}$.

In this case, point $A$ has the coordinates $(3,0)$ and point $C$ has the coordinates $(7,-8)$. We can finally solve for the length by finding the distance between them.

$AC = \sqrt{(7 -3)^2 +(-8 -0)^2} \\ AC = \sqrt{4^2 +(-8)^2} \\ AC = \sqrt{16 +64} \\ AC = \sqrt{80} \\ AC = \sqrt{4 \cdot 4 \cdot 5} \\ AC = 4\sqrt{5}$