Answer:
Step-by-step explanation:he first digit must be a 6, 7, or 8, because the number has to be bigger than 6,000.
The last digit must be a 1, 3, 5, or 7, because the number has to be odd.
So if the first digit is 6 or 8, there are 4 odd-number options for the last digit. If the first digit is a 7, then there are only 3 options for the last digit, as 7 can’t be used twice.
The other two digits can be anything that’s not already used. So for each first-and-last combination of digits mentioned above, there will be six options available for one of the middle digits, and then for each of those 3-digit combinations, five options will be available for the final remaining digit.
At this point, we have everything we need to express this as an equation:
x = (2 x 4 + 1 x 3) x 6 x 5
And then we can simplify and solve:
x = (8 + 3) x 30
x = 11 x 30
x = 330
you can find a_6:
