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ANEK [815]
2 years ago
11

4n<16 ; {1, 2, 3, 4} Select each correct answer. 1 2 3 4

Mathematics
1 answer:
ss7ja [257]2 years ago
3 0
The article is not north of north and the 2
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Simplify the following expression to remove negative exponents.
Talja [164]

When there is a negative exponent, you switch the side of the fraction it's on. If the negative exponent is the numerator or a whole number, like x^{-9} or \frac{x^{-9} }{3}, you move the exponent and its coefficient to the bottom so that it's part of the denominator, and remove the negative.

x^{-9} = \frac{1}{x^{9} }

\frac{x^{-9} }{3}= \frac{1}{3x^{9} }

If the exponent is on the bottom, or part of the denominator, like \frac{1}{x^{-4} }, we move it to the top and take out the negative.

\frac{1}{x^{-4} } = x^{4}

In our case, the expression is x^{-7}.

So, using our new knowledge of negative exponents, we can take the exponent and put it as a denominator.

x^{-7} = \frac{1}{x^7}

The answer would be the last answer.

hope this helps!

4 0
1 year ago
Solve equation 100-6r=160-10r
Verdich [7]
<span>100-6r=160-10r
Add 10r to both sides
100+4r=160
Subtract 100 from 160
4r=60
Divide 60 by 4
Final Answer: 15</span>
4 0
3 years ago
Read 2 more answers
Please help THIS SHOULD BE EASY
goldfiish [28.3K]

Answer:

c,d,f

Step-by-step explanation:

I hope these r the answers.

4 0
3 years ago
Read 2 more answers
Sarah took the advertising department from her company on a round trip to meet with a potential client. Including Sarah a total
IceJOKER [234]

Answer

20

Step By Step

its 20 maybe

7 0
3 years ago
A projectile is launched from ground level with a initial velocity of Vo feet per second. Neglecting air resistance, its height
antiseptic1488 [7]
The height at t seconds after launch is
s(t) = - 16t² + V₀t
where V₀ = initial launch velocity.

Part a:
When s = 192 ft, and V₀ = 112 ft/s, then
-16t² + 112t = 192
16t² - 112t + 192 = 0
t² - 7t + 12 = 0
(t - 3)(t - 4) = 0
t = 3 s, or t = 4 s

The projectile reaches a height of  192 ft at 3 s on the way up, and at 4 s on the way down.

Part b:
When the projectile reaches the ground, s = 0.
Therefore
-16t² + 112t = 0
-16t(t - 7) = 0
t = 0 or t = 7 s

When t=0, the projectile is launched.
When t = 7 s, the projectile returns to the ground.

Answer: 7 s

4 0
3 years ago
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