A coyote had 10 pups in her third litter. (10)
It was twice as many as in her second litter,( 2( second litter) = third litter
her second litter had 3 more pups than her first.( first litter +3)=2nd litter
Find the number of pups in her litter
Answer:
4/10, 0.4, 40%
1/4, 0.25, 25%
Hope this helps also "Hi" again. :)
Answer:
C, linear
Step-by-step explanation:
C is the only one with the (1,8) corriant
And it is linear because it has a pattern
2 x -6 equals 0. add 6 to both sides. divide both sides by two. x equals 3
N+d=34
.05n+.10d=2.60
Solve by substitution
n=34-d
.05(34-d)+.10d=2.60
1.7-.05d+.10d=2.60
.05d=.90
d=18 dimes
18+n=34
n=16 nickles