Hey ! there
Answer:
- <u>1</u><u>3</u><u> </u>is the answer .
Step-by-step explanation:
In this question we are provided with right angle triangle having <u>hypotenuse</u><u> </u><u>(</u><u> </u><u>longest </u><u>side </u><u>)</u><u> </u><u>=</u><u> </u><u>c </u><u>,</u><u> </u><u>perpendicular</u><u> </u><u>=</u><u> </u><u>5</u><u> </u><u>and </u><u>base </u><u>=</u><u> </u><u>1</u><u>2</u><u> </u><u>.</u> And we are asked to find the length of <u>missing side i.e. hypotenuse</u><u> </u>and if necessary we have to round it off to 2 decimal places.
We can find the missing side by using <u>Pythagorean</u><u> Theorem</u><u> </u><u>.</u> It states that sum of squares of perpendicular and base is equal to square in a right angle triangle that is ,
![\: \qquad \: \qquad \: \underline{\boxed{ \frak{H {}^{2} = P {}^{2} + B {}^{2} }}}](https://tex.z-dn.net/?f=%20%5C%3A%20%20%5Cqquad%20%20%5C%3A%20%5Cqquad%20%20%5C%3A%20%20%5Cunderline%7B%5Cboxed%7B%20%5Cfrak%7BH%20%7B%7D%5E%7B2%7D%20%20%3D%20P%20%20%7B%7D%5E%7B2%7D%20%2B%20B%20%7B%7D%5E%7B2%7D%20%7D%7D%7D)
<u>Where </u><u>,</u>
- H refers to <u>Hypotenuse</u>
- P refers to <u>Perpendicular</u>
- B r refers to <u>Base</u>
<u>SOLUTION</u><u> </u><u>:</u><u> </u><u>-</u>
Substituting value of hypotenuse as c , perpendicular as 5 and base as 12 in formula :
![\quad \longmapsto \qquad \: (c) {}^{2} = (5) {}^{2} + (12) {}^{2}](https://tex.z-dn.net/?f=%20%5Cquad%20%5Clongmapsto%20%5Cqquad%20%5C%3A%20%28c%29%20%7B%7D%5E%7B2%7D%20%20%3D%20%285%29%20%7B%7D%5E%7B2%7D%20%20%2B%20%2812%29%20%7B%7D%5E%7B2%7D%20)
Squaring 5 and 12 :
![\quad \longmapsto \qquad \:(c) {}^{2} = 25 + 144](https://tex.z-dn.net/?f=%20%5Cquad%20%5Clongmapsto%20%5Cqquad%20%5C%3A%28c%29%20%7B%7D%5E%7B2%7D%20%20%3D%2025%20%2B%20144)
Adding 25 and 144 :
![\quad \longmapsto \qquad \:(c) {}^{2} = 169](https://tex.z-dn.net/?f=%20%5Cquad%20%5Clongmapsto%20%5Cqquad%20%5C%3A%28c%29%20%7B%7D%5E%7B2%7D%20%20%3D%20169)
Applying square root to both sides :
![\quad \longmapsto \qquad \: \sqrt{(c) {}^{2} } = \sqrt{169}](https://tex.z-dn.net/?f=%20%5Cquad%20%5Clongmapsto%20%5Cqquad%20%5C%3A%20%5Csqrt%7B%28c%29%20%7B%7D%5E%7B2%7D%20%7D%20%20%3D%20%20%5Csqrt%7B169%7D%20)
On simplifying , We get :
![\quad \longmapsto \qquad \orange{\underline{\boxed{\frak{c = 13}}}} \quad \bigstar](https://tex.z-dn.net/?f=%20%5Cquad%20%5Clongmapsto%20%5Cqquad%20%20%20%20%20%5Corange%7B%5Cunderline%7B%5Cboxed%7B%5Cfrak%7Bc%20%3D%2013%7D%7D%7D%7D%20%5Cquad%20%5Cbigstar)
- <u>Henceforth</u><u> </u><u>,</u><u> </u><u>❝</u><u> </u><u>1</u><u>3</u><u> </u><u>❞</u><u> </u><u>is </u><u>the</u><u> </u><u>length </u><u>of </u><u>missing</u><u> </u><u>side </u><u>.</u>
<u>Verifying</u><u> </u><u>:</u><u> </u><u>-</u>
Now we are checking our answer by putting all values in formula . So ,
- <u>(</u><u> </u><u>1</u><u>3</u><u> </u><u>)</u><u>²</u><u> </u>= ( 5 )² + ( 12 )²
<u>Therefore</u><u> </u><u>,</u><u> </u><u>our </u><u>answer</u><u> is</u><u> correct</u><u> </u><u>.</u>
<h2>
<u>#</u><u>K</u><u>e</u><u>e</u><u>p</u><u> </u><u>Learning</u></h2>
Answer:
CD=66
Step-by-step explanation:
12x-30=6x+18
6x=48
x=8
12(8)-30=66
CD=66
Answer:
it's not
Step-by-step explanation:
they're the same numbers so either way you would arrange them it would either be seven groups of three or three groups of seven and the outcome would still be the same number because nothing really changed
Answer and Step-by-step explanation:
This is the same thing as:
<u>4.2 - (12 + x)</u>
The 4.2 is being subtracted by the value of 12 and a number, denoted as x.
<u><em>#teamtrees #PAW (Plant And Water)</em></u>
Answer:
Refer to the attachment.. hope this helps..