Answer:
50%
Explanation:
Both parent's genotype is Bb because they are hairless and alive.
If it has a homozygous dominant genotype (BB), the dog will die in utero.
If it has a heterozygous genotype (Bb), the dog will be hairless but won't die.
If it has a homozygous dominant genotype (bb), the dog will have hair.
The ratio of BB:Bb:bb is 1:2:1 meaning that there is a 50% probability of having a live hairless puppy.
Hope this helps! <3
Answer:
1) CO₂
2) 0.2551 g
Explanation:
The balanced reactions are:
CaCO₃ + 2HCl → CaCl₂ + H₂O + CO₂
MgCO₃ + 2HCl → MgCl₂ + H₂O + CO₂
1) The gas produced is CO₂.
2) Calculate mass of CaCO₃:
(0.5236 g) (0.4230) = 0.2215 g CaCO₃
Convert to moles:
(0.2215 g CaCO₃) (1 mol / 100.1 g) = 0.002213 mol CaCO₃
Find moles of CaCO₃:
(0.002213 mol CaCO₃) (1 mol CO₂ / mol CaCO₃) = 0.002213 mol CO₂
Convert to mass:
(0.002213 mol CO₂) (44.01 g / mol) = 0.09738 g CO₂
Calculate mass of MgCO₃:
(0.5236 g) (0.5770) = 0.3021 g MgCO₃
Convert to moles:
(0.3021 g MgCO₃) (1 mol / 84.31 g) = 0.003583 mol MgCO₃
Find moles of MgCO₃:
(0.003583 mol MgCO₃) (1 mol CO₂ / mol MgCO₃) = 0.003583 mol CO₂
Convert to mass:
(0.003583 mol CO₂) (44.01 g / mol) = 0.1577 g CO₂
Total mass of CO₂:
0.09738 g CO₂ + 0.1577 g CO₂ = 0.2551 g CO₂
Answer:
When a nerve impulse reaches the end of an axon, the axon releases chemicals called neurotransmitters. Neurotransmitters travel across the synapse between the axon and the dendrite of the next neuron.
Explanation:
The binding allows the nerve impulse to travel through the receiving neuron.
Answer:
B. food production
Explanation:
In the example above described, salinity conditions (3%) completely prevented radicle development (0 mm). Salinity conditions may alter plant development by inhibiting the uptake of nitrogen, and by limiting water intake. Moreover, it has been shown that the excessive accumulation of chloride ions in plant cells may have toxic effects on plant growth, causing ionic stress and thus leading to nutrient deficiency.
