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3 years ago

Pls factor 8a^2 b^3 c^3 - 64a^3 b^5 c^2

Mathematics

2 answers:

Firlakuza [10]3 years ago

7 0

Answer:

8a²b³c²(c - 8ab²)

Step-by-step explanation:

8a²b³c³ - 64a³ $b^{5}$ c² ← factor out 8a²b³c² from each term

= 8a²b³c²(c - 8ab²)

ArbitrLikvidat [17]3 years ago

6 0

Answer

8a2b3c2(−8ab2+c)

Step-by-step explanation:

Factor 8a2b3c3−64a3b5c2

−64a3b5c2+8a2b3c3

=8a2b3c2(−8ab2+c)

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Use the given information to find the measures of all angles formed by parallel lines a and b, and transversal m.

xeze [42]

Answer:

Either $77.5^{o}$ or $102.5^{o}$

Step-by-step explanation:

Given that : one angle is $25^{0}$ greater than another. Let the two angles be represented by a and b. Since one angle is $25^{0}$ greater than another, then:

b = a + $25^{0}$

But;

a + b = $180^{o}$ (sum of angles on a straight line)

a + a + $25^{0}$ = $180^{o}$

2a = $180^{o}$ - $25^{0}$

a = $77.5^{o}$

b = $77.5^{o}$ + $25^{0}$ = $102.5^{o}$

Therefore the measures of all angles formed by the lines is either $77.5^{o}$ or $102.5^{o}$ .

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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