All categories

4 years ago

What is y=1x-3 in standard form

Mathematics

2 answers:

ollegr [7]4 years ago

8 0

-x+y=-3. This is the answer since standard form is Ax+By=C

krek1111 [17]4 years ago

5 0

u can write it as y-x=-3

You might be interested in

The box plots of two sets of data are shown in the figure. What's the inter quartile range (IRQ) of both data sets? A. 10 B. 40

Mama L [17]

We cannot see the box plot. However to find the IQR of a box plot, it is the rectangle in the middle. The amount in the middle is your answer.

4 0

3 years ago

Use technology or a z-score table to answer the question.

Alik [6]

Answer:

The second choice: Approximately $65.2\%$ of the pretzel bags here will contain between 225 and 245 pretzels.

Step-by-step explanation:

This explanation uses a z-score table where each $z$ entry has two decimal places.

Let $\mu$ represent the mean of a normal distribution of variable $X$ . Let $\sigma$ be the standard deviation of the distribution. The z-score for the observation $x$ would be:

$\displaystyle z = \frac{x - \mu}{\sigma}$ .

In this question,

$\mu = 240$ .
$\sigma = 9.3$ .

Calculate the z-score for $x_1 = 225$ and $x_2 = 245$ . Keep in mind that each entry in the z-score table here has two decimal places. Hence, round the results below so that each contains at least two decimal places.

$\begin{aligned} z_1 &= \frac{x_1 - \mu}{\sigma} \\ &= \frac{225 - 240}{9.3} \approx -1.61\end{aligned}$ .

$\begin{aligned} z_2 &= \frac{x_2 - \mu}{\sigma} \\ &= \frac{245 - 240}{9.3} \approx 0.54\end{aligned}$ .

The question is asking for the probability $P(225 \le X \le 245)$ (where $X$ is between two values.) In this case, that's the same as $P(-1.61 \le Z \le 0.54)$ .

Keep in mind that the probabilities on many z-table correspond to probability of $P(Z \le z)$ (where $Z$ is no greater than one value.) Therefore, apply the identity $P(z_1 \le Z \le z_2) = P(Z \le z_2) - P(Z \le z_1)$ to rewrite $P(-1.61 \le Z \le 0.54)$ as the difference between two probabilities:

$P(-1.61 \le Z \le 0.54) = P(Z \le 0.54) - P(Z \le -1.61)$ .

Look up the z-table for $P(Z \le 0.54)$ and $P(Z \le -1.61)$ :

$P(Z \le 0.54)\approx 0.70540$ .
$P(Z \le -1.61) \approx 0.05370$ .

$\begin{aligned}& P(225 \le X \le 245) \\ &= P\left(\frac{225 - 240}{9.3} \le Z \le \frac{245 - 240}{9.3}\right)\\&\approx P(-1.61 \le Z \le 0.54) \\ &= P(Z \le 0.54) - P(Z \le -1.61)\\ &\approx 0.70540 - 0.05370 \\& \approx 0.65.2 \\ &= 65.2\% \end{aligned}$ .

3 0

3 years ago

Which sampling strategy is best to use when not all of the members of a population are easily accessible for survey?A. Simple ra

Ivahew [28]

It's D convenience hoped that helped

3 0

3 years ago

Anu

bija089 [108]

Answer:

Circumference of Circle B=19.625cm

Step-by-step explanation:

The circumference formula is: 2pie(r) = pie(d)

We have diameter of the first circle which is 6. Now, because the diameter of second circle is 25% greater than this,

Hence, we add 25% in 6:

6+25/100 =6+0.25=6.25 cm

Therefore, we have diameter of 6.25 for circle B.

Now, we need to find the circumference of the Circle A.

circumference= pie(d) = pie(6)= 3.14times6= 18.84

Now use the proportional reasoning to find Circumference of Circle B:

circumference of Circle A/diameter Circle A = circumference of Circle B/diameter Circle B

18.84/6=circumference of Circle B/6.25

Cross multiply and divide:

(18.84times6.25)/6 = Circumference of Circle B

Solve:

Circumference of Circle B=19.625cm

Hope this helps!

Mark brainliest if you think i helped! Would really appreciate!

7 0

3 years ago

(polynomials) multiply. (x^2-5x)(2x^2+x-3)

Nikitich [7]

Answer:

2x^4 - 9x^3 -8x^2 + 15x

Step-by-step explanation:

(x^2-5x)(2x^2+x-3) distribute first

2x^4

x^2 + x = x^3

5 * 2x^2 x= 10x^3

5x^1+1 = 5x^2

5 * 3x = 15x Put them all together

2x^4 + x^3 - 3x^2 - 10x^3 - 5x^2 + 15x Like terms

2x^4 + x^3 -10x^3 - 3x^2- 5x^2 + 15x Add similar terms

= 2x^4 + x^3 - 10x^3 - 8x^2 + 15x more adding terms

2x^4 - 9x^3 -8x^2 + 15x

Hope my answer has helped you, if not i'm sorry.

5 0

3 years ago

Read 2 more answers