The answer is false due to the object is changes shape not size
Answer:
f your number is x, then the difference between that number and 8 would be x-8. Twice that is 2(x-8)
Three times the sum of the number and 3 would be 3(x+3). So, you get the equation:
2(x-8)=3(x+3)
2x-16=3x+9
x=-25
Answer:
Step-by-step explanation:
![\dfrac 12 \left[\sin(a+b)+\sin(a-b) \right]\\\\\\=\dfrac 12\left[ 2 \sin a \cos b\right]\\\\\\=\sin a \cos b](https://tex.z-dn.net/?f=%5Cdfrac%2012%20%5Cleft%5B%5Csin%28a%2Bb%29%2B%5Csin%28a-b%29%20%5Cright%5D%5C%5C%5C%5C%5C%5C%3D%5Cdfrac%2012%5Cleft%5B%202%20%5Csin%20a%20%5Ccos%20b%5Cright%5D%5C%5C%5C%5C%5C%5C%3D%5Csin%20a%20%5Ccos%20b)
Answer:0
Step-by-step explanation:
