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Vlada [557]
2 years ago
8

The distribution of actual weight of tomato soup in a 16 ounce can is thought to be be shaped with a ean equal to 16 ounces, and

a standard deviation equal to 0.25 ounces. Based on this information, between what two values could we expect 95% of all cans to weigh?
(a) 15.75 to 16.25 ounces

(b) 15.50 to 16.50 ounces

(c) 15.25 to 16.75 ounces

(d) 15 to 17 ounces
Mathematics
1 answer:
Rudiy272 years ago
8 0

Answer:

(b) 15.50 to 16.50 ounces

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed(bell shaped) random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 16

Standard deviation = 0.25

Based on this information, between what two values could we expect 95% of all cans to weigh?

By the Empirical Rule, within 2 standard deviations of the mean. So

16 - 2*0.25 = 15.50 ounces

16 + 2*0.25 = 16.50 ounces

So the corret answer is:

(b) 15.50 to 16.50 ounces

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Find the uncertainty in a calculated average speed from the measurements of distance and time. Average speed depends on distance
zzz [600]

Answer:

\frac{\Delta v}{v}=0.426

Step-by-step explanation:

you have that the average sped is given by the following formula:

v(x,t)=\frac{x}{t}

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\frac{\Delta v}{v}=\sqrt{(\frac{\Delta x}{x})^2+(\frac{\Delta t}{t})^2}        (1)

Δv: uncertainty in speed

Δx: uncertainty in the distance = 0.9m

Δt: uncertainty in time = 0.7s

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t: time = 1.7s

You replace the values of all parameters in the equation (1):

\frac{\Delta v}{v}=\sqrt{(\frac{0.9}{8.1})^2+(\frac{0.7}{1.7})^2}\\\\\frac{\Delta v}{v}=0.426

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4 0
3 years ago
3.18x+2.6+0.9x+x=28<br> Solve please, brainliest will be awarded
Elis [28]

Answer:

x=5

Step-by-step explanation

3.18x+2.6+0.9x+x=28

3.18x+0.9x+x+2.6=28

5.08x+2.6=28

5.08x+2.6-2.6=28-2.6

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hope it helps

8 0
3 years ago
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PLEASE PLEASE HELP! Find the measure of APB^.
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Answer:

65°

Step-by-step explanation:

Radii CA and CB are perpendicular to tangent lines AT and BT, so

\angle CAT=\angle CBT=90^{\circ}

Since angle BAT is equal to 65°, angle CAB has measure

\angle CAB=90^{\circ}-65^{\circ}=25^{\circ}.

Consider triangle ACB. This triangle is isosceles, because CA=CB as radii of the circle. Two angles adjacent to the base are congruent, thus

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The sum of the measures of all interior angles in triangle is always 180°, so

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Angle ACB is central angle subtended on the minor arc AB, angle APB is inscribed angle subtended on the same minor arc AB. The measure of inscribed angle is half the measure of central angle subtended on the same arc, so

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