Answer:
Step-by-step explanation:
Here's how you convert:
The little number outside the radical, called the index, serves as the denominator in the rational power, and the power on the x inside the radical serves as the numerator in the rational power on the x.
A couple of examples:
![\sqrt[3]{x^4}=x^{\frac{4}{3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E4%7D%3Dx%5E%7B%5Cfrac%7B4%7D%7B3%7D)
![\sqrt[5]{x^7}=x^{\frac{7}{5}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7Bx%5E7%7D%3Dx%5E%7B%5Cfrac%7B7%7D%7B5%7D)
It's that simple. For your problem in particular:
is the exact same thing as ![\sqrt[3]{7^1}=7^{\frac{1}{3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B7%5E1%7D%3D7%5E%7B%5Cfrac%7B1%7D%7B3%7D)
5.3g + 9 = 2.3g + 15
5.3g + 9 - 9 = 2.3g + 15 - 9
5.3g = 2.3g + 6
5.3g - 2.3g = 2.3g - 2.3g + 6
3g = 6
3g / 3 = 6 / 3
g = 2
It is a similar triangle so the side length of the smaller triangle (x and x-2) are in the same ratio as the bigger triangle (2x+5 and 2x-1). As the ratio is the same, you can equate them and solve for x.
Answer:
y= -1= 3(x -3)
Step-by-step explanation:
y -y1= m(x -x1)
y -1= 3(x -3)
A
explanation:
2x+10=-6-30
8x+40=0
x=-5