Separate the variables:

Separate the left side into partial fractions. We want coefficients a and b such that





So we have

Integrating both sides yields






With the initial condition y(0) = 1, we find

so that the particular solution is

It's not too hard to solve explicitly for y; notice that

Then






The distributive property is used when you have a value multiplied by 2 values separated by an operation.
For example, if you have x (y + z), then you would use the distributive property to get x (y + z) = xy + xz.
The # 1 the answer is A
# 2 C
Answer:
Step-by-step explanation:
m÷350 = 299
m = 299×350 = 104,650
So you have to solve 7-8x=1 and 7-8x=-1. Then you check your solutions. Always make sure to check for extraneous solutions!! Always. Hope this helps!!