Question

Anyone help me do this am giving the brainliest

Answer 1

Answer:

112 km

Explanation:

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Answer 2

Explanation:

The first step is to write the 1st condition of equilibrium, which states that the net force acting on the beam is zero:

$F_{net} = 5\:\text{kN} + N_L + N_R - 40\:\text{kN} - 60\:\text{kN} = 0$

where $N_L$ and $N_R$ are reaction forces at the beam supports on the left and right, respectively.

Next, the 2nd condition of equilibrium states that the net torque about a pivot point is zero. Let's choose the location of the left beam support as our pivot point, which will make the torque due to $N_L$ is equal to zero. Let us also assume that the counterclockwise direction produces positive torque. So we can write

$\tau_{net} = (40\:\text{kN})(2\:\text{m}) + (5\:\text{kN})(5\:\text{m}) \\+ N_R(7\:\text{m}) - (60\:\text{kN})(8\:\text{m}) = 0$

$\Rightarrow 80\:\text{kN-m} + 25\:\text{kN-m} + N_R(7\:\text{m}) \\= 480\:\text{kN-m}$

Solving for $N_R,$ we see that

$N_R = 53.6\:\text{kN}$

Putting this value into our 1st equation, we find that the reaction force $N_L$ is

$N_L = 100\:\text{kN} - 5\:\text{kN} - N_R$

$\:\:\:\:\:\:\:\:= 41.4\:\text{kN}$