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Anna71 [15]
2 years ago
6

How does the tension in your arms compare when you let yourself dangle motionless by both arms and by one arm

Physics
1 answer:
PolarNik [594]2 years ago
6 0

When you support yourself with two arms, the tension in each arm is half of the tension you experience when you support your weight with only one arm.

The tension in your arm is directly proportional to the weight of your body.

T = W = mg

When you support your weight with your two arms;

  • the upward force balancing the downward force due to the weight of your body will be distributed equally in both arms.

Tension \ in \ each \ arm = \frac{Total \ weight \ of \ your \ body}{2}

When you support the weight of your body with one arm,

  • the upward force balancing the downward force due to your weight will be on only one arm

Tension \ in \ the \ one \ arm = Total \ weight \ of \ your \ body

Thus, when you support yourself with two arms, the tension in each arm is half of the tension you experience when you support your weight with only one arm.

Learn more here: brainly.com/question/13443419

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What is the equivalent resistance of a circuit that contains three 10.0 12
lana66690 [7]

Answer:

Explanation:

The equivalent resistance for three resistors connected in parallel is given as

(1/R)=(1/R₁)+(1/R₂)+(1/R₃)

now we.need to.insert the value of 3 resistances but only 2 are given in the question.

3 0
3 years ago
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A ferris wheel with radius 12 m makes a revolution every 3 minutes. Find the linear (tangental) speed of a passenger. How far do
Alina [70]

Answer:

The linear (tangential) speed of a passenger is 0.4188 m/s

The distance traveled by the person in 5 minutes ride is 125.64 m

Explanation:

Given;

radius of the Ferris, r = 12 m

1 revolution per 3 minutes, \omega = \frac{2\pi (radian)}{3\ (minutes)} *\frac{1\ minute}{60 \ seconds} = 0.0349 \ rad/s

The linear (tangential) speed of a passenger is given by;

v = ωr

v = (0.0349)(12)

v = 0.4188 m/s

The distance traveled by the person in 5 minutes ride is given by;

d = vt

d = (0.4188)(5 x 60)

d = 125.64 m

3 0
3 years ago
Help me frfr I don’t understand
Art [367]

The points are

(1,10)

(6,0)

\boxed{\sf slope(m)=\dfrac{y_2-y_1}{x_2-x_1}}

\\ \sf\longmapsto m=\dfrac{0-10}{6-1}

\\ \sf\longmapsto m=\dfrac{-10}{5}

\\ \sf\longmapsto m=-2

6 0
3 years ago
What is the magnitude of the net force needed to bring a 2110 kg car to rest from 18.1 m/s in 7.0 seconds?
lozanna [386]
Here is what we know:
a = ?, s = ?, u = 18.1m/s, v = zero/rest, t = 7.0s, m = 2110kg

(a = acceleration, s= displacement, u = initial velocity, v = final velocity, t = time and m is mass)

Now we choose a kinematic formula. Since we know v, u and t, we will use the formula: v = u+at and rearrange it so that we can find a.
a = v-u/t
a = 0-18.1/7.0 = -2.5857...
therefore, a = -2.6m/s

We have our acceleration, now let’s find the net force. To find the force we use one of Newtons laws of motion.
We will use Newtons second law since it describes what happens when one or more forces act upon an object.
F = ma
F = (2110kg)(-2.6m/s)
F = -5486 kg
Therefore the net force F = -5486 N
4 0
4 years ago
An object is placed 18 cm in front of spherical mirror.if the image is formed at 4cm to the right of the mirror, calculate it's
ivolga24 [154]
1) Focal length

We can find the focal length of the mirror by using the mirror equation:
\frac{1}{f}= \frac{1}{d_o}+ \frac{1}{d_i} (1)
where 
f is the focal length
d_o is the distance of the object from the mirror
d_i is the distance of the image from the mirror

In this case, d_o = 18 cm, while d_i=-4 cm (the distance of the image should be taken as negative, because the image is to the right (behind) of the mirror, so it is virtual). If we use these data inside (1), we find the focal length of the mirror:
\frac{1}{f}= \frac{1}{18 cm}- \frac{1}{4 cm}=- \frac{7}{36 cm}
from which we find
f=- \frac{36}{7} cm=-5.1 cm

2) The mirror is convex: in fact, for the sign convention, a concave mirror has positive focal length while a convex mirror has negative focal length. In this case, the focal length is negative, so the mirror is convex.

3) The image is virtual, because it is behind the mirror and in fact we have taken its distance from the mirror as negative.

4) The radius of curvature of a mirror is twice its focal length, so for the mirror in our problem the radius of curvature is:
r=2f=2 \cdot 5.1 cm=10.2 cm
3 0
4 years ago
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