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Anna71 [15]
2 years ago
6

How does the tension in your arms compare when you let yourself dangle motionless by both arms and by one arm

Physics
1 answer:
PolarNik [594]2 years ago
6 0

When you support yourself with two arms, the tension in each arm is half of the tension you experience when you support your weight with only one arm.

The tension in your arm is directly proportional to the weight of your body.

T = W = mg

When you support your weight with your two arms;

  • the upward force balancing the downward force due to the weight of your body will be distributed equally in both arms.

Tension \ in \ each \ arm = \frac{Total \ weight \ of \ your \ body}{2}

When you support the weight of your body with one arm,

  • the upward force balancing the downward force due to your weight will be on only one arm

Tension \ in \ the \ one \ arm = Total \ weight \ of \ your \ body

Thus, when you support yourself with two arms, the tension in each arm is half of the tension you experience when you support your weight with only one arm.

Learn more here: brainly.com/question/13443419

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One day, after pulling down your window shade, you notice that sunlight is passing through a pinhole in the shade and making a s
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Complete Question

One day, after pulling down your window shade, you notice that sunlight is passing through a pinhole in the shade and making a small patch of light on the far wall. Having recently studied optics in your physics class, you're not too surprised to see that the patch of light seems to be a circular diffraction pattern. It appears that the central maximum is about 2 cm across, and you estimate that the distance from the window shade to the wall is about 5 m.

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Estimate the diameter of the pinhole.  

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The diameter is  d =0.000336 m

Explanation:

     From the question we are told that

            The central maxima is D= 2cm = \frac{2}{100} = 0.02m

            The distance from the window shade is L = 5m

     The  average wavelength of the  sun is mathematically evaluated as

                         \lambda_{ave } = \frac{\lambda_i  + \lambda_f}{2}

 Generally the visible light spectrum  has a wavelength  range  between  400 nm  to 700 nm  

        So  the initial wavelength of the sun is \lambda _i = 400nm

           and the final wavelength is  \lambda_f = 700nm

  Substituting this into the above equation

                 \lambda_{sun} = \frac{400nm  +700nm}{2}

                        = 550nm

The diameter is evaluated as

              d = \frac{2.44 \lambda_{sun} L}{D}

substituting values

              d = \frac{2.44 * 550*10^{-9} * 5 }{0.02}

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<u>S</u><u>u</u><u>g</u><u>a</u><u>r</u><u>:</u><u>-</u>

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<u>C</u><u>o</u><u>r</u><u>n</u><u> </u><u>s</u><u>y</u><u>r</u><u>u</u><u>p</u><u>:</u><u>-</u>

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