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Anna71 [15]
2 years ago
6

How does the tension in your arms compare when you let yourself dangle motionless by both arms and by one arm

Physics
1 answer:
PolarNik [594]2 years ago
6 0

When you support yourself with two arms, the tension in each arm is half of the tension you experience when you support your weight with only one arm.

The tension in your arm is directly proportional to the weight of your body.

T = W = mg

When you support your weight with your two arms;

  • the upward force balancing the downward force due to the weight of your body will be distributed equally in both arms.

Tension \ in \ each \ arm = \frac{Total \ weight \ of \ your \ body}{2}

When you support the weight of your body with one arm,

  • the upward force balancing the downward force due to your weight will be on only one arm

Tension \ in \ the \ one \ arm = Total \ weight \ of \ your \ body

Thus, when you support yourself with two arms, the tension in each arm is half of the tension you experience when you support your weight with only one arm.

Learn more here: brainly.com/question/13443419

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Answer:

the formula is efficiency = output / input × 100%

7 0
3 years ago
A 29.0 kg beam is attached to a wall with a hi.nge while its far end is supported by a cable such that the beam is horizontal.
castortr0y [4]

The vertical component of force exerted by the hi.nge on the beam will be,142.10N.

To find the answer, we need to know more about the tension.

<h3>How to find the vertical component of the force exerted by the hi.nge on the beam?</h3>
  • Let's draw the free body diagram of the system.
  • To find the vertical component of the force exerted by the hi.nge on the beam, we have to balance the total vertical force to zero.

                      F_V+T sin\alpha -mg=0\\F_V=mg-Tsin\alpha \\

  • To find the answer, we have to find the tension,

                     Tlsin\alpha - mg\frac{l}{2}sin\beta =0\\ \\Tlsin\alpha = mg\frac{l}{2}sin\beta\\\\Tsin57=\frac{mg}{2}sin90\\\\T=\frac{mg}{2sin57} =169.43N

  • Thus, the vertical component of the force exerted by the hi.nge on the beam will be,

                F_V=(29*9.8)-(169.43*sin57)=142.10N

Thus, we can conclude that, the vertical component of force exerted by the hi.nge on the beam will be,142.10N.

Learn more about the tension here:

brainly.com/question/28106868

#SPJ1

5 0
2 years ago
Read 2 more answers
15. You are watching a baseball game on television that 15
Gre4nikov [31]

Answer:

t_total = 6.99 s

Explanation:

It asks us how long it takes to hear the sound, for this we must look for the time (t₁) it takes for the sound to reach the microphone, the time it takes for the video signal (t₂) to reach the television and the time (₃) it takes for the TV sound to reach us, so the total delay time is

         t_total = t₁ + t₂ + t₂

we look for t1, it indicates that the distance x = 22m

          v = x / t

           t = x / v

           t₁ = 22/343

           t₁ = 6.41 10-2 s

time t₂

          t₂ = 4500 103/3 108

          t₂ = 1.5 10-5 s

time t₃

          t₃ = 2/343

          t₃ = 5.83 10⁻³

Total time is

         t_total = t₁ + t₂ + t₃

         t_total = 6.41 10⁻² + ​​1.5 10⁻⁵ + 0.583 10⁻²

         t_total = 6.99 s

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