How does the tension in your arms compare when you let yourself dangle motionless by both arms and by one arm
1 answer:
When you support yourself with two arms, the tension in each arm is half of the tension you experience when you support your weight with only one arm.
The tension in your arm is directly proportional to the weight of your body.
T = W = mg
When you support your weight with your two arms;
- the upward force balancing the downward force due to the weight of your body will be distributed equally in both arms.
When you support the weight of your body with one arm,
- the upward force balancing the downward force due to your weight will be on only one arm
Thus, when you support yourself with two arms, the tension in each arm is half of the tension you experience when you support your weight with only one arm.
Learn more here: brainly.com/question/13443419
You might be interested in
Answer:
t = 1.41 sec.
Explanation:
If we assume that the acceleration of the blocks is constant, we can apply any of the kinematic equations to get the time since the block 2 was released till it reached the floor.
First, we need to find the value of acceleration, which is the same for both blocks.
If we take as our system both blocks, and think about the pulley as redirecting the force simply (as tension in the strings behave like internal forces) , we can apply Newton's 2nd Law, as they were moving along the same axis, aiming at opposite directions, as follows:
F = m₂*g - m₁*g = (m₁+m₂)*a (we choose as positive the direction of the acceleration, will be the one defined by the larger mass, in this case m₂)
⇒ a = ( = g/5 m/s²
Once we got the value of a, we can use for instance this kinematic equation, and solve for t:
Δx = 1/2*a*t² ⇒ t² = (2* 1.96m *5)/g = 2 sec² ⇒ t = √2 = 1.41 sec.