(-2.6) - 3.8 Help me plsss
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Dos rectas cuyas pendientes son m1 y m2, son perpendiculares si y sólo si m1m2 =-1
with a point and the slope you can find the equation
y-y1=m(x-x1)
as the point is given (-1,-4) then substitute it in the equation
y-(-4)= -2[(x-(-1)]⇒y+4= -2x-2⇒y=-2x-2-4⇒y=-2x-6 and this is the equation of the line that must be graphed
second step)
graph the equation y =- 2x-6, with the points of intersection are for x = 0, y = -2(0)-6= -6 , the point is ( 0,-6) and the other point is for y = 0
0= -2x-6, 2x= -6, x = -6/ 2 = -3, the other point is (-3,0) then the graph is the following, you can see in it the points of intersection
