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zheka24 [161]
3 years ago
12

Use the Rational Zeros Theorem to write a list of all potential rational zeros f(x) = 14x^3 + 56x^2 + 2x - 7

Mathematics
1 answer:
Crank3 years ago
3 0
The factors of 7are -1 and 7 or 1 and -7, the factors of 14 are 1, 2, 7, and 14, or -1,  -2, -7,-14. so the list of potential zeros are: 1/1, 1/2, 1/7, 1/14, 7/1,7/2, 7/7, 7/14, which can be simplified into 1, 1/2,1/7, 1/14, 7, 7/2
add the negative ones: -1, -1/2,-1/7, -1/14, -7, -7/2
I believe there are a total of 12 potential zeros
reference: 
http://www.sparknotes.com/math/algebra2/polynomials/section4.rhtml

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Answer:

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Step-by-step explanation:

According to Question , We have a circle With Centre 'O' & Area 48\pi .

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Now We Have Two Points Given On Circle Q & R , P Is Circumcentre Of Triangle QRO .

Thus A Circle Can Also Be Formed with Centre P . ( See attachment For Diagram )

Now The Diameter of Circle With Centre P = Radius Of Circle with Centre O

so Radius Of Circle With Centre P(r_{2}) = \frac{\sqrt{48}}{2}

Now We Have To Find Area Of Equilateral Triangle .

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A= \frac{\sqrt{3} }{4} * \frac{\sqrt{48} }{2}*\frac{\sqrt{48} }{2}

The Area Of PQR is = 3\sqrt{3}

For Diagram , Please Find In Attachment

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Answer:

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Step-by-step explanation:

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