Answer:
306.8 feet
Step-by-step explanation:
Refer the attached figure .
A surveyor moves 160 feet away from the base of the pole i.e. ED = 160 m
Referring the image .
AC=ED=160 m
A transit i.e. AE is 6 feet tall.
AE = CD=6 feet
With a transmit the angle of elevation to the top of the pole to be 62° i.e. ∠BAC = 62°
To Find BC , use tigonometric ratio.
Now, the height of the pole = BC+CD =300.8+6=306.8 feet
Hence the height of the pole is 306.8 feet
Answer:
1 is 0.6 and 2 is 612 3 is 39.2 and 4 is -3 and 5 is 9/4 or (2 1/4)
Step-by-step explanation:
:)
So when you are trying to find the solution to the system of equations make sure that you have it where y= -4/5x-6 and y= -30 are written like this:
-30=-4/5x-6
And then solve for x:
Add 6 on both sides.
-24=-4/5x
Then multiply by the reciprocal of -4/5.
-5/4*-24=-5/4*-4/5x
x=30
But then you are gonna want to plug 30 in for x in y=-4/5x-6 to make sure that it is the same as y=-30.
10 liters of gas fill one tank.
x liters of gas fill x/10 tanks.
35 liters of gas fills 35/10=7/2 tanks
7/2 can also be written as 3.5 or the mixed number (3 and 1/2)
The length of TY is 2.26.
Solution:
In ΔTRY, θ = 37°, Adjacent side = 3.
To find the length of TY.
Using trigonometry identity,
TY = 2.26
Hence the length of TY is 2.26.
