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3 years ago

5x + 12 + 3x = 6(x + 4) Please Show Work.

Mathematics

2 answers:

Len [333]3 years ago

8 0

5x + 12 + 3x = 6(x + 4)

5x+3x+12=6(x+4)

Multiply the bracket by 6

(6)(x)(6)(+4)=6x+24

5x+3x+12=6x+24

8x+12=6x+24

Move 6x to the other side. Sign changes from +6x to -6x.

8x-6x+12=6x-6x+24

8x-6x+12=24

2x+12=24

Move 12 to the other side. Sign changes from +12 to -12.

2x+12-12=24-12

2x=12

Divide by 2 for both sides.

2x/2=12/2

x=6

Answer: x=6

castortr0y [4]3 years ago

5 0

The answer is x= 6
This is how I got the answer

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3 years ago

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weeeeeb [17]

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3 years ago

Add. (6x3+3x2−2)+(x3−5x2−3) Express the answer in standard form.

sergiy2304 [10]

Answer:

$7x^3-2x^2-5$

Step-by-step explanation:

We need to add the two terms.

$(6x^3+3x^2-2)+(x^3-5x^2-3)$

Solving,

Combine the like terms and adding those terms

$(6x^3+3x^2-2)+(x^3-5x^2-3)\\=6x^3+3x^2-2+x^3-5x^2-3\\=6x^3+x^3+3x^2-5x^2-2-3\\=7x^3-2x^2-5$

So, the answer is:

$7x^3-2x^2-5$

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3 years ago

The radius of one circle is three the time radius of another circle. The sum of their areas is 12pi. Find the radius of each cir

zlopas [31]

$\displaystyle\\
\begin{cases}
R_1 = 3R_2\\
\pi R_1^2 +\pi R_2^2=12\pi ~~~\Big|~~:\pi 
\end{cases} \\ \\ 
\begin{cases} 
R_1 = 3R_2\\
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\end{cases} \\ \\ 
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9R_2^2 + R_2^2=12 \\ \\ 
10R_2^2=12\\\\
R_2^2 = \frac{12}{10} = \frac{6}{5} \\ \\ 
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3 years ago

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sattari [20]

8y - 11y + 6

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3 years ago