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sergey [27]
3 years ago
14

283,980 in word form

Mathematics
1 answer:
Alex777 [14]3 years ago
7 0

Answer:

Two hundred eighty-three thousand, nine hundred eighty

Step-by-step explanation:

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Choose the graph 12-4×>8
Sergeu [11.5K]

Answer:

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Step-by-step explanation:

8 0
3 years ago
A 55m and 35m broad park is surrounded by a 2.5m wide path.
daser333 [38]

Step-by-step explanation:

☄ \underline {\underline{ \text{Given}}} :

  • Length of a park ( l ) = 55 m
  • Breadth of a park ( b ) = 35 m
  • Width running outside the park ( d ) = 2.5 m
  • Rate of paving the path with stones = Rs 120 per sq.metre

☄ \underline{ \underline{ \text{To \: find}}}:

  • Area of the park
  • Cosy of paving the path with stones at Rs 130 per sq.metre

☄ \underline{ \underline{ \text{Solution}}} :

Part 1 : \boxed{\text{Area \:of \:a \:path \: running \:outside = 2d(l + b + 2d)}}

plug the known values and simplify :

⟹ \sf{2 \times 2.5(55 + 35 + 2 \times 2.5)}

⟹ \sf{5  \times 95}

⟹ \sf{475 \:  {m}^{2} }

Part 2 : \boxed{ \sf{Total \: cost = Area \: of \: paths \:  \times  Rate}}

⟹ \sf{475  \times 120}

⟹\sf{Rs \: 57000}

\purple{ \boxed{ \boxed{ \sf{ \tt{⟿ \: Our \: final \: answer : (i) = 475 \:  {m}^{2}   \:  and \: (ii ) = Rs \: 57000}}}}}

Hope I helped ! ♡

Have a wonderful day /night ツ

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Verbal expression for 3x^2
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One expression could be three x to the power of two. Let me know if that's right :)
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If you're going to use technology (Brainly) to solve this problem, you might find you get a quicker answer using the technology of your graphing calculator.

It is often convenient to cast the problem in the form f(θ) = 0. You can do that by adding 1 to both sides of the equation.

4\sqrt{2}\cos{(\theta)}+4=0\\ \cos{(\theta)}+\dfrac{1}{\sqrt{2}}=0\qquad\mbox{divide by $4\sqrt{2}$}\\ \cos{(\theta)}=\dfrac{-\sqrt{2}}{2}\qquad\mbox{subtract $\dfrac{1}{\sqrt{2}}$}\\\\ \theta=\{\dfrac{3\pi}{4},\dfrac{5\pi}{4}\}\qquad\mbox{determine the corresponding angles}

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4 x 4 5/6 simplify equation
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= 856

Step-by-step explanation:

im not sure :) ....

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