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Lapatulllka [165]
2 years ago
8

Help me to solve this question​

Mathematics
1 answer:
soldier1979 [14.2K]2 years ago
4 0
73 cm I think this is the right answer
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If a water tank already contains 55 gallons of water when baxter begins to fill it and water is flowing in at a rate of 8 gallon
saw5 [17]

Answer:

I think it would be 55+8x. I hope this helps. :)

Step-by-step explanation:

55 gallons of water

8 gallons per minute

It would be 55 gallons (the original amount in the tank) plus 8 gallons per minute. (8x)

x = how many minutes the tank is being filled up more.

so if you were to fill up the tank another 5 minutes, the equation would be 55+8(5)

55+40

95 would be the answer.

6 0
3 years ago
An adult elephant that is 10 ft tall casts a shadow that is 15 ft long. Find the length of the shadow that is a 8 ft telephone b
Fittoniya [83]

Answer:

12 feet long bc of cross multiplying then dividing the product by 10 which gives you 12!

5 0
3 years ago
What is the value of x?<br> 4 3<br> 11<br> 36<br> 16<br> 0 17/<br> 7<br> 16
trasher [3.6K]

Answer:..Step-by-step explanation:

8 0
3 years ago
Crawling Crayfish!
boyakko [2]

Answer: Crayfish, 25 s

Step-by-step explanation:

Given

The length of race is 60 cm

Flicker gets a 10 cm head-start

Cray fish covers 6 cm in 5 s i.e. its speed is

\Rightarrow \dfrac{6}{5}=1.2\ cm/s

Flicker covers 4 cm in 5 s, its speed is

\Rightarrow \dfrac{4}{5}=0.8\ cm/s

Time taken by Cray fish to cover the race is

\Rightarrow t_1=\dfrac{60}{1.2}\\\\\Rightarrow t_1=50\ s

Time taken by flicker to cover race with 10 cm head start

\Rightarrow t_2=\dfrac{60-10}{0.8}\\\\\Rightarrow t_2=62.5\ s

Time taken by crayfish is less. Hence, crayfish wins the race

When they both covers the same distance, they tied momentarily i.e.

\Rightarrow 1.2t=10+0.8t\\\Rightarrow 0.4t=10\\\\\Rightarrow t=\dfrac{10}{0.4}\\\\\Rightarrow t=25\ s

After 25 s, they tied the race.

5 0
3 years ago
3x +2 = 9x + 20 for x
Semmy [17]

Answer:

Use a calculator solved :)))

Step-by-step explanation:

7 0
3 years ago
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