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stepan [7]
3 years ago
9

Which equation would you use to solve the problem," Four less than the product of 3 and a number is 15"

Mathematics
2 answers:
mel-nik [20]3 years ago
7 0

Answer:

The correct option is a) 3n - 4 = 15

Step-by-step explanation:

The product of 3 and a number means 3 multiplied by a number (n)

So it'll be 3*n or simply 3n

Now, it says 4 less than the product

So 4 less than 3n

That is equal to 3n minus 4 or 3n -4

So we come to the conclusion that

3n - 4 = 15

Hope this helps!

geniusboy [140]3 years ago
5 0
The answer is a. 3n - 4 = 15
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2 years ago
Question 12 (1 point)
Paraphin [41]
<h3>Answer:   5</h3>

=================================================

Explanation:

Let's consider the expression (x-y)^2. It expands out to x^2-2xy+y^2. The terms are:

  • x^2
  • -2xy
  • y^2

Each of those terms either has a single variable with an exponent of 2, or has the exponents add to 2. Think of 2xy as 2x^1y^1.

In short, this means that the degree of each monomial term is 2.

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Now consider (x-y)^3. It expands out into x^3-3x^2y+3xy^2+y^3.

We have terms that either have a single variable and the exponent is 3, or the exponents add to 3. The degree of each term is 3.

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This pattern continues.

In general, for (x-y)^n, where n is any positive whole number, the degree of each term in the expansion is n. If you picked any term, added the exponents, then the exponents will add to n.

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2 years ago
Match the circle equations in general form with their corresponding equations in standard form. x2 y2 − 4x 12y − 20 = 0 (x − 6)2
frosja888 [35]

The equation given is matched with the respective vertex forms.

<h3>What is the standard Equation for a circle ?</h3>

The standard equation for a circle is given by

(x-h)² + (y-k)² = r²

The equation given in the question are

x² + y²  − 4x + 12y − 20 = 0

(x − 6)²  + (y − 4)²  = 56

x²  + y²  + 6x − 8y − 10 = 0

(x − 2)²  + (y + 6)²  = 60

3x²  + 3y²  + 12x + 18y − 15 = 0

(x + 2)²  + (y + 3)²  = 18

5x²  + 5y²  − 10x + 20y − 30 = 0

(x+3)²  + (y-4)²  = 35

2x²  + 2y²  − 24x − 16y − 8 = 0

(x-1)²  + (y+2)²   = 11

The first equation is

x² + y²  − 4x + 12y − 20 = 0

It can be written ad

x² -4x + 4 - 4 +y²+12y +36-36 -20 = 0

(x-2)² +(y+6)²= 60

The second equation is

x²  + y²  + 6x − 8y − 10 = 0

x² +6x +9-9 +y²  -8y +16-16 -10 = 0

(x+3)²  + (y-4)²  = 35

The third equation is

3x²  + 3y²  + 12x + 18y − 15 = 0

(x + 2)²  + (y + 3)²  = 18

The fourth equation is

5x²  + 5y²  − 10x + 20y − 30 = 0

(x-1)²  + (y+2)²   = 11

The fifth equation is

2x²  + 2y²  − 24x − 16y − 8 = 0

(x − 6)²  + (y − 4)²  = 56

To know more about standard equation of Circle

brainly.com/question/13658927

#SPJ1

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