Please round it to the third decimal point.

Mathematics

1 answer:

nasty-shy [4]2 years ago

8 0

Answer:22022635.627

Step-by-step explanation:

photo math

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The team ran

juin [17]

The team ran 2 miles.

Step-by-step explanation:

Step 1; The track is $\frac{3}{4}$ miles long and the team ran 2 $\frac{2}{3}$ laps on it. To calculate the distance run we multiply the number of laps ran with the distance on each lap.

Distance run = Number of laps × Distance on each lap.

Step 2; We convert 2 $\frac{2}{3}$ from a mixed fraction into an improper fraction. To do this, we multiply the whole number with the denominator of the fraction and add with it the numerator of the same fraction whereas the denominator remains unchanged. To convert the fraction 2 $\frac{2}{3}$ = ((2 × 3) + 2) / 3 = $\frac{8}{3}$ .

Distance run = Number of laps × Distance on each lap = $\frac{8}{3}$ × $\frac{3}{4}$ = $\frac{8}{4}$ = 2 miles.

3 0

3 years ago

Read 2 more answers

A grocery store will only accept yellow onions that are at least 3 inches in diameter. A grower has a crop of onions with diamet

Marizza181 [45]

<span>For the answer to the question above,this is a simple question.

z = (3.25-3.5)/.25= -1
p= .8413
then multiply 100 to get the percentage.
The answer will be
84.13% or 84% rounded to the whole number.
I hope my answer helped you with your problem above. Have a nice day</span>

5 0

2 years ago

Graph the function defined by f(x) = (x+21)

Inga [223]

Answer:

Step-by-step explanation:

Consider the parent function $y=|x|.$ The graph of this function is represented as red graph in attached diagram.

Now consider the function $y=|x+2|.$

Remind main translations of the graph of the function $y=f(x):$

$y=f(x-a)$ - translation a units to the right;
$y=f(x+a)$ - translation a units to the left;
$y=f(x)+a$ - translation a units up;
$y=f(x)-a$ - translation a units down.

In your case, the graph of the function $y=|x+2|$ is translated graph of the function $y=|x|$ 2 units to the left (blue graph). So, correct answer is option A.