Work out a: a/5 +3 =8<br> a/5 is a fraction and i need to find out what A is

Juans three math quizzes this week took him 1/3?4/6?and1/5 hour to complete. List all the fraction from least to greatest

Alex

Answer:

$\frac{1}{5}$ , $\frac{1}{3}$ , $\frac{4}{6}$ .

Step-by-step explanation:

Given fractions $\frac{1}{3}$ , $\frac{4}{6}$ , $\frac{1}{5}$ .

We need to list them from least to greatest.

In order to arrange them from least to greatest, we need to find the least common denominator of $\frac{1}{3}$ , $\frac{4}{6}$ , $\frac{1}{5}$ .

We have 3, 6 and 5 in denominators.

Least common multiple of 3, 6 and 5 is = 30, because 30 is least number that can be divided by all three number 3, 6 and 5.

Let us covert each denominator as 30.

Multiplying first fraction $\frac{1}{3}$ by 10 in top and bottom, we get

$\frac{1}{3} = \frac{1\times10}{3\times10}=\frac{10}{30}$

Multiplying first fraction $\frac{4}{6}$ by 5 in top and bottom, we get

$\frac{4}{6} = \frac{4\times5}{6\times5}=\frac{20}{30}$

Multiplying first fraction $\frac{1}{5}$ by 6 in top and bottom, we get

$\frac{1}{5} = \frac{1\times6}{5\times6}=\frac{6}{30}.$

Now, we can check $\frac{10}{30}, \frac{20}{30} \ and \ \frac{6}{30}.$

$\frac{6}{30}$ is the smallest, $\frac{10}{30}$ is greater and $\frac{20}{30}$ is the greatest.

Therefore, we can arrange fractions $\frac{6}{30}, \frac{10}{30} \ and \ \frac{20}{30}.$

Writing original fractions in place of equivalent fractions, we can write

$\frac{1}{5}$ , $\frac{1}{3}$ and $\frac{4}{6}$ .

Therefore, the order the amounts of paint from least to greatest is:

$\frac{1}{5}$ , $\frac{1}{3}$ , $\frac{4}{6}$ .

4 0

3 years ago

What is the equation of the line through (1, 6) and (0, 2)?

ASHA 777 [7]

Answer:

y = 4x + 2

Step-by-step explanation:

y = mx + b

m is the slope

b is the y-intercept

6 0

3 years ago

3. The area of a rectangular deck, in square meters, is given by the polynomial 40p2 + 24p.

lorasvet [3.4K]

Answer:

Length = 5p + 3

Perimeter = 26p + 6

Step-by-step explanation:

Given

Area = 40p² + 24p

Width = 8p

Solving for the length of deck

Given that the deck is rectangular in shape.

The area will be calculated as thus;

Area = Length * Width

Substitute 40p² + 24p and 8p for Area and Width respectively

The formula becomes

40p² + 24p = Length * 8p

Factorize both sides

p(40p + 24) = Length * 8 * p

Divide both sides by P

40p + 24 = Length * 8

Factorize both sides, again

8(5p + 3) = Length * 8

Multiply both sides by ⅛

⅛ * 8(5p + 3) = Length * 8 * ⅛

5p + 3 = Length

Length = 5p + 3

Solving for the perimeter of the deck

The perimeter of the deck is calculated as thus

Perimeter = 2(Length + Width)

Substitute 5p + 3 and 8p for Length and Width, respectively.

Perimeter = 2(5p + 3 + 8p)

Perimeter = 2(5p + 8p + 3)

Perimeter = 2(13p + 3)

Open bracket

Perimeter = 2 * 13p + 2 * 3

Perimeter = 26p + 6

4 0

4 years ago

Thirty elves would like to build a skating ring so they can all use it at the same time. Santa tells them, they need at least 40

Delicious77 [7]

Answer:

The Possible dimension of the ring could be;

20 ft × 60 ft

25 ft × 48 ft

30 ft × 40 ft

60 ft × 20 ft

48 ft × 25 ft

40 ft × 30 ft

Step-by-step explanation:

Given:

Number of skaters = 30

Area for each skater = 40 sq ft

We need to find the dimension of rectangular ring the are going to build.

Now we know that they building the skating ring such that they all can use at same time.

Hence if the all use at same time then we will find the total area first.

Total area can be calculated by multiplying Number of skaters with area required for each skaters.

Framing the equation we get;

Total area = $30\times 40 = 1200 \ ft^2$

Hence The total area of the rectangular ring would be 1200 sq. ft.

Now we know that Total area is equal to product of length and width.

$length\times width =1200ft^2$

1200 can be written as = 20 × 60, 25 × 48, 30 × 40,60 × 20,48 × 25,40 × 30

Hence the Possible dimension of the ring could be;

20 ft × 60 ft

25 ft × 48 ft

30 ft × 40 ft

60 ft × 20 ft

48 ft × 25 ft

40 ft × 30 ft

3 0

3 years ago

A teenager who is 5 feet tall throws an object into the air. The quadratic function LaTeX: f\left(x\right)=-16x^2+64x+5f ( x ) =

tia_tia [17]

Answer:

At approximately x = 0.08 and x = 3.92.

Step-by-step explanation:

The height of the ball is modeled by the function:

$f(x)=-16x^2+64x+5$

Where f(x) is the height after x seconds.

We want to determine the time(s) when the ball is 10 feet in the air.

Therefore, we will set the function equal to 10 and solve for x:

$10=-16x^2+64x+5$

Subtracting 10 from both sides:

$-16x^2+64x-5=0$

For simplicity, divide both sides by -1:

$16x^2-64x+5=0$

We will use the quadratic formula. In this case a = 16, b = -64, and c = 5. Therefore:

$\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Substitute:

$\displaystyle x=\frac{-(-64)\pm\sqrt{(-64)^2-4(16)(5)}}{2(16)}$

Evaluate:

$\displaystyle x=\frac{64\pm\sqrt{3776}}{32}$

Simplify the square root:

$\sqrt{3776}=\sqrt{64\cdot 59}=8\sqrt{59}$

Therefore:

$\displaystyle x=\frac{64\pm8\sqrt{59}}{32}$

Simplify:

$\displaystyle x=\frac{8\pm\sqrt{59}}{4}$

Approximate:

$\displaystyle x=\frac{8+\sqrt{59}}{4}\approx 3.92\text{ and } x=\frac{8-\sqrt{59}}{4}\approx0.08$

Therefore, the ball will reach a height of 10 feet at approximately x = 0.08 and x = 3.92.

7 0

3 years ago

Work out a: a/5 +3 =8 a/5 is a fraction and i need to find out what A is