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3 years ago

Work out a: a/5 +3 =8 a/5 is a fraction and i need to find out what A is

Mathematics

1 answer:

mylen [45]3 years ago

4 0

Answer:

Step-by-step explanation:

a/5+3=8

a/5=8-3

a/5=5

cross multiply

a=5×5

a=25

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11. In circle H, if mDHG = (11x - 36)* and mGHF = (x + 12), find mDG.

Dima020 [189]

mˆDG=151∘∘

An arc’s length means the same commonsense thing length always means — you know, like the length of a piece of string

4 0

3 years ago

What is 9 superscript 7 written in expanded form? 9 + 9 + 9 + 9 + 9 + 9 + 9 9 times 9 times 9 times 9 times 9 times 9 times 9 7

GrogVix [38]

Answer:

4,782,969

Step-by-step explanation:

9^7

Written in expanded form = 9 times 9 times 9 times 9 times 9 times 9 times 9

= 9 × 9 × 9 × 9 × 9 × 9 × 9

= 4,782,969

9^7 means multiplying 9 in 7 places

9^7 = 4,782,969

3 0

2 years ago

Read 2 more answers

Help me plz I’ve never been good with math

S_A_V [24]

Its 16.

So you have 12 miles on that trail, and markers every 2/3 of the way there. If you were to divide 2 with 3 then you can get the decimal of the fraction. Which in this case it’s 0.75. So every single 0.75 of the mile there is a marker. Divide 12 with 0.75 and you get 16 markers.

Hoped this helped in some way.

4 0

3 years ago

Find the mass of the lamina that occupies the region D = {(x, y) : 0 ≤ x ≤ 1, 0 ≤ y ≤ 1} with the density function ρ(x, y) = xye

Alona [7]

Answer:

The mass of the lamina is 1

Step-by-step explanation:

Let $\rho(x,y)$ be a continuous density function of a lamina in the plane region D,then the mass of the lamina is given by:

$m=\int\limits \int\limits_D \rho(x,y) \, dA$ .

From the question, the given density function is $\rho (x,y)=xye^{x+y}$ .

Again, the lamina occupies a rectangular region: D={(x, y) : 0 ≤ x ≤ 1, 0 ≤ y ≤ 1}.

The mass of the lamina can be found by evaluating the double integral:

$I=\int\limits^1_0\int\limits^1_0xye^{x+y}dydx$ .

Since D is a rectangular region, we can apply Fubini's Theorem to get:

$I=\int\limits^1_0(\int\limits^1_0xye^{x+y}dy)dx$ .

Let the inner integral be: $I_0=\int\limits^1_0xye^{x+y}dy$ , then

$I=\int\limits^1_0(I_0)dx$ .

The inner integral is evaluated using integration by parts.

Let $u=xy$ , the partial derivative of u wrt y is

$\implies du=xdy$

and

$dv=\int\limits e^{x+y} dy$ , integrating wrt y, we obtain

$v=\int\limits e^{x+y}$

Recall the integration by parts formula: $\int\limits udv=uv- \int\limits vdu$

This implies that:

$\int\limits xye^{x+y}dy=xye^{x+y}-\int\limits e^{x+y}\cdot xdy$

$\int\limits xye^{x+y}dy=xye^{x+y}-xe^{x+y}$

$I_0=\int\limits^1_0 xye^{x+y}dy$

We substitute the limits of integration and evaluate to get:

$I_0=xe^x$

This implies that:

$I=\int\limits^1_0(xe^x)dx$ .

$I=\int\limits^1_0xe^xdx$ .

We again apply integration by parts formula to get:

$\int\limits xe^xdx=e^x(x-1)$ .

$I=\int\limits^1_0xe^xdx=e^1(1-1)-e^0(0-1)$ .

$I=\int\limits^1_0xe^xdx=0-1(0-1)$ .

$I=\int\limits^1_0xe^xdx=0-1(-1)=1$ .

No unit is given, therefore the mass of the lamina is 1.

3 0

3 years ago

A spinner has three sections. The table shows the results of spinning the arrow on the spinner 80 times. What is the experimenta

mihalych1998 [28]

The experimental probability is

(number of times it stopped over Sect. 2) / (total number of times you tried it)

Number of times it stopped in Section-2: 36

Total number of times you tried it: (20 + 36 + 24) = 80

Experimental probability of Section-2 = 36/80 = 9/20 = 45%

8 0

3 years ago