3.5 years (so 4 years)
2500×0.065 (this gets the amout earned per year) =162.5
568.75÷162.5 (how many years to get the desired amount) =3.5
<em>Hey</em>
<em>The</em><em> </em><em>value</em><em> </em><em>of</em><em> </em><em>X </em><em>is</em><em> </em><em>3</em><em>5</em><em>°</em>
<em>X</em><em> </em><em>and</em><em> </em><em>3</em><em>5</em><em>°</em><em> </em><em>are</em><em> </em><em>vertically</em><em> </em><em>opposite</em><em> </em><em>angles</em><em>.</em>
<em>Vertically</em><em> </em><em>opposite</em><em> </em><em>angles</em><em> </em><em>are</em><em> </em><em>always</em><em> </em><em>equal</em><em>.</em>
<em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em>
<em>Good</em><em> </em><em>luck</em><em> on</em><em> your</em><em> assignment</em>
Answer:
a) Average velocity at 0.1 s is 696 ft/s.
b) Average velocity at 0.01 s is 7536 ft/s.
c) Average velocity at 0.001 s is 75936 ft/s.
Step-by-step explanation:
Given : If a ball is thrown straight up into the air with an initial velocity of 70 ft/s, its height in feet after t seconds is given by
.
To find : The average velocity for the time period beginning when t = 2 and lasting. a. 0.1 s.
, b. 0.01 s.
, c. 0.001 s.
Solution :
a) The average velocity for the time period beginning when t = 2 and lasting 0.1 s.





b) The average velocity for the time period beginning when t = 2 and lasting 0.01 s.





c) The average velocity for the time period beginning when t = 2 and lasting 0.001 s.



