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salantis [7]
2 years ago
6

The Equation (y-y1)=m(x-x1) represents the point-slope form of a linear equation.Which equation can be used to find y1?

Mathematics
1 answer:
trapecia [35]2 years ago
5 0

Answer:

Step-by-step explanation:

The first one

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The volume of a cylinder is 628 cm3. Find the radius of the base if the cylinder
kirza4 [7]
Radius is 5 cm. is the answer

8 0
2 years ago
2. The mean birth weight of a full term boy born in the US is 7.7 lbs, with standard deviation of 1.1 lbs. A. Find the probabili
Fed [463]

Answer:

A

The value is P( X  <  7 ) =0.26226

B

The value is P( X  <  7 ) = 0.00073

Step-by-step explanation:

From the question we are told that

  The population mean is  \mu = 7.7 lbs

   The standard deviation is \sigma  = 1.1 \ lbs

  The sample size is  n =  25

Generally the probability that a boy born full term in the US weighs less than 7 lbs is mathematically represented as

     P( X  <  7 ) =  P( \frac{X - \mu }{\sigma}  <  \frac{7 - 7.7 }{1.1 } )

\frac{X -\mu}{\sigma }  =  Z (The  \ standardized \  value\  of  \ X )

=>   P( X  <  7 ) =  P(Z

From the z table  the area under the normal curve to the left corresponding to    -0.6364  is

    P(Z

=>   P( X  <  7 ) =0.26226

Generally the standard error of mean is mathematically represented as  

       \sigma_{x} = \frac{\sigma }{\sqrt{n} }

=>     \sigma_{x} = \frac{ 1.1  }{\sqrt{25} }

=>     \sigma_{x} = 0.22

Generally the probability that the average weight of 25 baby boys born in a particular hospital have an average weight less than 7 lbs is mathematically represented as

         P( \= X  <  7 ) =  P( \frac{\= X - \mu }{\sigma_{x}}  <  \frac{7 - 7.7 }{ 0.22 } )

=>      P( X  <  7 ) =  P(Z

From the z table  the area under the normal curve to the left corresponding to    -3.1818  is

=>      P(Z

=>      P( X  <  7 ) = 0.00073

4 0
2 years ago
Solve:<br><br> r<br> 5<br> - 6 = -1
Leona [35]
That's right, 5- 6= -1
3 0
3 years ago
Read 2 more answers
Is there any systematic tendency for part-time college faculty to hold their students to different standards than do full-time f
alexandr1967 [171]

Answer:

H0 : μ1 - μ2 = 0

H1 : μ1 - μ2 ≠ 0

-1. 34

0.1837

Step-by-step explanation:

Full time :

n1 = 125

x1 = 2.7386

s1 = 0.65342

Part time :

n2 = 88

x2 = 2.8439

s2 = 0.49241

H0 : μ1 - μ2 = 0

H1 : μ1 - μ2 ≠ 0

Test statistic :

The test statistic :

(x1 - x2) / sqrt[(s1²/n1 + s2²/n2)]

(2.7386 - 2.8439) / sqrt[(0.65342²/125 + 0.49241²/88)]

−0.1053 / sqrt(0.0034156615712 + 0.0027553)

-0.1053 /0.0785554

= - 1.34

Test statistic = - 1.34

The Pvalue :

Using df = smaller n - 1 = 88 - 1 = 87

Pvalue from test statistic score ;

Pvalue = 0.1837

Pvalue > α ; We fail to reject the null and conclude that the GPA does not differ.

At α = 0.01 ; the result is insignificant

6 0
2 years ago
N is the midpoint of AC; AN = 4x - 7 and NC = 5x - 15<br> Find NC=
coldgirl [10]

Answer:

A____N____C

AN= NC

4x-7=5x-15

5x-4x= 15-7

x= 8

NC = 5x-15=5(8) – 15 = 40 – 15 = 25

I hope I helped you^_^

4 0
2 years ago
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