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Nesterboy [21]
4 years ago
13

Trey has plastic cubes stored in a box that measures 4 ft long, 212 ft wide, and 2 ft tall. The edge length of each plastic cube

is 12 ft. How many plastic cubes can fit into the box?
Mathematics
2 answers:
castortr0y [4]4 years ago
6 0
Your answer would be 160 had it on a test

hope this helps
ICE Princess25 [194]4 years ago
6 0

Answer: There are 160 plastic cubes that can fit into the box.

Step-by-step explanation:

Since we have given that

Length of box = 4 ft

Width of box = 212 ft

Height of box = 2 ft

As we know that the formula for "Volume of cuboid":

Volume=Length\times Width\times Height\\\\Volume=4\times 2\frac{1}{2}\times 2\\\\Volume=4\times \frac{5}{2}\times 2\\\\Volume=20\ ft^3

And we have

Edge length of each plastic = \frac{1}{2}\ ft

As we know that the formula for "Volume of cube":

Volume=Side^3\\\\Volume=\frac{1}{2}\times \frac{1}{2}\times \frac{1}{2}\\\\Volume=\frac{1}{8}\ ft^3

So, Number of plastic cubes can fit into the box is given by

\frac{\text{ Volume of box}}{\text{ Volume of plastic cube}}\\\\=\frac{20}{\frac{1}{8}}\\\\=20\times 8\\\\=160

Hence, there are 160 plastic cubes that can fit into the box.

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12. P (7,r) = 5040. Find r<br><br>A. 5<br>B. 6<br>C. 7<br>D. 8​
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Answer:

B

Step-by-step explanation:

P(7,r) = 5040

P(n,r)=\dfrac{n!}{(n - r)!}\\\\\\n = 7 \\\\\dfrac{7!}{(7 - r)!}=5040\\\\\\7! = (7-r)!*5040\\\\(7-r)!=\dfrac{5040}{7*6*5*4*3*2*1}\\\\\\(7-r)!=\dfrac{5040}{5040}\\\\\\(7-r)!=1\\\\

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