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irakobra [83]
2 years ago
9

8,902 to the nearest thousand

Mathematics
2 answers:
7nadin3 [17]2 years ago
5 0

Answer:

9,000

Step-by-step explanation:

Bess [88]2 years ago
3 0
Answer: 9000

Reason: If any number after the thousands place (in this situation) is greater than 5 you round.
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Step-by-step explanation:

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Order them least to greatest. And explain
AnnyKZ [126]

Answer:

13. 1/2, 5/8, 3/4

16. 7/12, 3/5, 2/3

Step-by-step explanation:

make them have the same denominator.

13) 1/2 x 4 = <u>4/8</u>, <u>5/8</u>, 3/4 x 2= <u>6/8</u>

16) Grab two fractions let's say 3/5 and 2/3

Multiply 3/5 denominator (5) with 2/3 numerator (2)

It's 10 and place it above the number you multiplied the numerator from so it's above 2/3.  Do it again but with 2/3 denominator (3) and 3/5 numerator (3). Multiply 3 and 3 you get 9. Place the 9 above 3/5. We know that 9 is less than 10 so 3/5 is less than 2/3. You can do this with any two fractions.

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3 years ago
Solve the system of equations.
Xelga [282]

Answer:

  b.  x=1, y=2, z=3

Step-by-step explanation:

The system of equations ...

  • 3x +2y +z = 10
  • 9x -6y +z = 0
  • x -y -3z = -10

has solution (x, y, z) = (1, 2, 3) . . . . matches choice B.

_____

While it is convenient to solve this using a graphing calculator or web site, one can easily solve the system by hand.

Subtract the second equation from 3 times the first:

  3(3x +2y +z) -(9x -6y +z) = 3(10) -(0)

  12y + 2z = 30 . . . . simplify

Dividing this result by 2 gives ...

  6y +z = 15 . . . . . . [eq4]

Subtract 3 times the third equation from the first:

  (3x +2y +z) -3(x -y -3z) = (10) -3(-10)

  5y +10z = 40 . . . . simplify

  y + 2z = 8 . . . . . . . divide by 5 . . . . . [eq5]

The two equations [eq4] and [eq5] can be solved any of the ways you usually solve two equations in two variables. Here, we'll use the first equation to write an expression for z that we can substitute into the second equation.

  z = 15 -6y . . . . . subtract 6y from [eq4]

  y + 2(15 -6y) = 8 . . . . . substitute for z in [eq5]

  -11y +30 = 8 . . . . . simplify

  -11y = -22 . . . . . . . subtract 30

  y = 2 . . . . . . . . . . . divide by the coefficient of y

  z = 15 -6(2) = 3 . . . . substitute for y in our equation for z

Substituting these values for y and z into the third original equation gives ...

  x - 2 -3(3) = -10

  x -11 = -10 . . . . . . . . simplify

  x = 1 . . . . . . . . . . . . add 11

The solution to the above system of equations is (x, y, z) = (1, 2, 3).

_____

<em>Comment on the problem statement</em>

Math is generally unforgiving of imprecision. The given system of equations has no variable "z", and some other typos are apparently involved. That is why we rewrote the system to the equations shown above.

It is very easy to mistake z for 2, or g for 9, or o for 0, or 1 for 7. There are other confusions that are possible, as well. Letters I (eye) and l (ell) are easily confused, and may be confused with 1 (one) as well. Sometimes y and 4, or 4 and 9, can also be written so as to be difficult to tell apart. Great care must be taken when handwriting these symbols.

7 0
3 years ago
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