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Marizza181 [45]
3 years ago
6

What is the median for the set of data? 6, 7, 10, 12, 12, 13 12 7 10 11

Mathematics
1 answer:
djverab [1.8K]3 years ago
8 0

Answer:

The median for the set of data is

11

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Find the angle between u =the square root of 5i-8j and v =the square root of 5i+j.
fenix001 [56]

Answer:

The angle between vector \vec{u} = 5\, \vec{i} - 8\, \vec{j} and \vec{v} = 5\, \vec{i} + \, \vec{j} is approximately 1.21 radians, which is equivalent to approximately 69.3^\circ.

Step-by-step explanation:

The angle between two vectors can be found from the ratio between:

  • their dot products, and
  • the product of their lengths.

To be precise, if \theta denotes the angle between \vec{u} and \vec{v} (assume that 0^\circ \le \theta < 180^\circ or equivalently 0 \le \theta < \pi,) then:

\displaystyle \cos(\theta) = \frac{\vec{u} \cdot \vec{v}}{\| u \| \cdot \| v \|}.

<h3>Dot product of the two vectors</h3>

The first component of \vec{u} is 5 and the first component of \vec{v} is also

The second component of \vec{u} is (-8) while the second component of \vec{v} is 1. The product of these two second components is (-8) \times 1= (-8).

The dot product of \vec{u} and \vec{v} will thus be:

\begin{aligned} \vec{u} \cdot \vec{v} = 5 \times 5 + (-8) \times1 = 17 \end{aligned}.

<h3>Lengths of the two vectors</h3>

Apply the Pythagorean Theorem to both \vec{u} and \vec{v}:

  • \| u \| = \sqrt{5^2 + (-8)^2} = \sqrt{89}.
  • \| v \| = \sqrt{5^2 + 1^2} = \sqrt{26}.

<h3>Angle between the two vectors</h3>

Let \theta represent the angle between \vec{u} and \vec{v}. Apply the formula\displaystyle \cos(\theta) = \frac{\vec{u} \cdot \vec{v}}{\| u \| \cdot \| v \|} to find the cosine of this angle:

\begin{aligned} \cos(\theta)&= \frac{\vec{u} \cdot \vec{v}}{\| u \| \cdot \| v \|} = \frac{17}{\sqrt{89}\cdot \sqrt{26}}\end{aligned}.

Since \theta is the angle between two vectors, its value should be between 0\; \rm radians and \pi \; \rm radians (0^\circ and 180^\circ.) That is: 0 \le \theta < \pi and 0^\circ \le \theta < 180^\circ. Apply the arccosine function (the inverse of the cosine function) to find the value of \theta:

\displaystyle \cos^{-1}\left(\frac{17}{\sqrt{89}\cdot \sqrt{26}}\right) \approx 1.21 \;\rm radians \approx 69.3^\circ .

3 0
2 years ago
WHATS 3 + 2??? I CANT FIGURE IT OUT. 50 POINTS FOR YOU​
Marizza181 [45]

Answer:

5

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
PLEASE HURRY, ZOOM IN TO SEE IT BETTER
zlopas [31]

Answer:

(2,7)

Step-by-step explanation:

You read it from the point were they intersect

6 0
3 years ago
6. The population of a town is 680 000 correct to the nearest 10 000. Write down
serg [7]

Answer:

a) 675 000

b) 685 000

Step-by-step explanation:

The population of a town is 680 000 correct to the nearest 10 000.

a) To find it lower bound, we level of accuracy by 2 and then subtract from 680 000

The lower bound is:

680 000-5000=675,000

Therefore the least possible population of the town is 675 000

b) We repeat the same process to find the upper bound

680 000+5000=685,000

6 0
3 years ago
A cone and a sphere both have a radius of 1. If you fill the cone with liquid, and pour it into the sphere, it fits exactly. Wha
PtichkaEL [24]

Answer and Step-by-step explanation:

First, solve for the volume of the sphere, then solve for the height of the cone using the volume of the sphere (which is said to be equal to the volume of the cone) and the radius given.

<u>Volume formula of Sphere</u>

V = \frac{4}{3} \pi r^2

<u>Substitute 1 in for r</u>

\frac{4}{3} \pi (1)^2 = \frac{4}{3} \pi  = 4.189 = Volume

<u>Finding the Height of a Cone</u>

Volume formula for Cone: V = \pi r^2\frac{h}{3}

<u />

<u>Solve for </u><u><em>h</em></u>

Multiply both sides by 3, then divide by pi and r^2.

h = \frac{3V}{\pi r^2}

<u>Plug in the volume and the radius.</u>

h = \frac{3(4.189)}{\pi (1)^2}

<u>Simplify</u>

h = \frac{12.567}{\pi }

h ≈ 4

<u>4 is approximately the height.</u>

<u></u>

<u></u>

<u><em>#TeamTrees #PAW (Plant And Water)</em></u>

6 0
3 years ago
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