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gregori [183]
2 years ago
9

Calculate the area in square metres for a triangle with a base 16.6 m long and a perpendicular height of

Mathematics
1 answer:
fomenos2 years ago
6 0

\\ \tt\bull\leadsto Area=\dfrac{1}{2}Base\times Height

\\ \tt\bull\leadsto Area=\dfrac{1}{2}16.6\times 3.2

\\ \tt\bull\leadsto Area=8.3(3.2)

\\ \tt\bull\leadsto Area=26.56m^2

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Answer:

284 is the answer

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The point P=\left(-\frac{\sqrt{33}}{7},\,\, y\right)P=(− 7 33 ​ ​ ,y) lies on the unit circle shown below. What is the value of
kifflom [539]

Answer:

y = √-1040/7

Step-by-step explanation:

The equation of a unit circle is expressed as;

x²+y² = 1

Given the coordinate of P = (-33/7, y)

Substitute the coordinate into the give expression and find y;

(-33/7)²+y² = 1

Expand

y² = 1-(-33/7)²

According to difference of two square

y² = (1+(-33/7))1-(-33/7))

y² = (1-33/7)(1+33/7)

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y= √-1040/49

y = √-1040/√49

y = √-1040/7

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4 0
2 years ago
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garri49 [273]

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2 years ago
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