All categories

2 years ago

Calculate the area in square metres for a triangle with a base 16.6 m long and a perpendicular height of

Mathematics

1 answer:

fomenos2 years ago

6 0

$\\ \tt\bull\leadsto Area=\dfrac{1}{2}Base\times Height$

$\\ \tt\bull\leadsto Area=\dfrac{1}{2}16.6\times 3.2$

$\\ \tt\bull\leadsto Area=8.3(3.2)$

$\\ \tt\bull\leadsto Area=26.56m^2$

You might be interested in

Which number is an irrational number?

chubhunter [2.5K]

I think A
PLEASEE GIVE ME BRAINLIEST

4 0

2 years ago

Read 2 more answers

I hope this can help you very much .

inna [77]

No because Carmella rounded both of the numbers down. Because she rounded it down to 300+10 there will not be enough space

Hope this helps

4 0

3 years ago

Evaluate the expression for p = -1<br> -38p2 - 78p

eduard

Answer:

$- 38 {p}^{2} - 78p \\ p = - 1 \\ - 38 \times { (- 1)}^{2} - 78 \times - 1 \\ - 38 + 78 \\ = 40 \\ thank \: you$

7 0

2 years ago

Read 2 more answers

Twice a number decreased by 8 is 2 less than half the number. What is the number?

iogann1982 [59]

Answer:

Step-by-step explanation:

2x - 8 = x + 10

- x - x

x - 8 = 10

+ 8 + 8

x = 18

8 0

3 years ago

Read 2 more answers

at a particular high school, 42% of the students participate in sports and 25% of the students participate in drama. if 53% of t

baherus [9]

The probability that a student participates in both sports and drama is $0.14$ .

<h3>What is the formula for P(AUB), where A and B are any two events?</h3>

If $A$ and $B$ are any two events, then the probability of the joint event $(A\cup B)$ is given by the following formula: $P(A\cup B)=P(A)+P(B)-P(A\cap B)$

Given that 42% of the students participate in sports and 25% of the students participate in drama and 53% of the students participate in either sports or drama.

Suppose $S$ denotes that "a student participates in sports" and $D$ denotes that "a student participates in drama".
So, we have $P(S)=\frac{42}{100}=0.42$ , $P(D)=\frac{25}{100}=0.25$ , $P(S\cup D)=\frac{53}{100}=0.53$ .

We want to find the probability that a student participates in both sports and drama i.e., we want to find $P(S\cap D)$ .

By the above formula, we obtain:

$P(S\cup D)=P(S)+P(D)-P(S\cap D)\\\Longrightarrow P(S\cap D)=P(S)+P(D)-P(S\cup D)\\\Longrightarrow P(S\cap D)=0.42+0.25-0.53\\\therefore P(S\cap D)=0.14=\frac{14}{100}$

Therefore, the probability that a student participates in both sports and drama is $0.14$ .

To learn more about probability, refer: brainly.com/question/24756209

#SPJ9

6 0

1 year ago

Read 2 more answers