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2 years ago

What is the slope (-3,1) (4,5)

Mathematics

2 answers:

givi [52]2 years ago

8 0

Slope is: (change in x)/(change in y)
Use point slope form: (y2-y1)/(x2-x1)

myrzilka [38]2 years ago

7 0

The slope in short is:
4/7

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How do I solve 28.8=18x

kolezko [41]

28.8 = 18x....divide both sides by 18, eliminating the 18 on the right side
28.8 / 18 = x
1.6 = x <==

3 0

2 years ago

Suppose that X is a random variable with mean 30 and standard deviation 4. Also suppose that Y is a random variable with mean 50

Vladimir79 [104]

Answer:

a) Var[z] = 1600

D[z] = 40

b) Var[z] = 2304

D[z] = 48

c) Var[z] = 80

D[z] = 8.94

d) Var[z] = 80

D[z] = 8.94

e) Var[z] = 320

D[z] = 17.88

Step-by-step explanation:

In general

V([x+y] = V[x] + V[y] +2Cov[xy]

how in this problem Cov[XY] = 0, then

V[x+y] = V[x] + V[y]

Also we must use this properti of the variance

V[ax+b] = $a^{2}$ V[x]

and remember that

standard desviation = $\sqrt{Var[x]}$

a) z = 35-10x

Var[z] = $10^{2}$ Var[x] = 100*16 = 1600

D[z] = $\sqrt{1600}$ = 40

b) z = 12x -5

Var[z] = $12^{2}$ Var[x] = 144*16 = 2304

D[z] = $\sqrt{2304}$ = 48

c) z = x + y

Var[z] = Var[x+y] = Var[x] + Var[y] = 16 + 64 = 80

D[z] = $\sqrt{80}$ = 8.94

d) z = x - y

Var[z] = Var[x-y] = Var[x] + Var[y] = 16 + 64 = 80

D[z] = $\sqrt{80}$ = 8.94

e) z = -2x + 2y

Var[z] = 4Var[x] + 4Var[y] = 4*16 + 4*64 = 320

D[z] = $\sqrt{320}$ = 17.88

7 0

2 years ago

Find the x and y intercepts of the quadratic equation f(x)=-x^2+4x-4

earnstyle [38]

X - Intercept
f(x) = -x² + 4x - 4
 0 = -x² + 4x - 4
 x = -(4) +/- √((4)² - 4(-1)(-4))
 2(-1)
 x = -4 +/- √(16 - 16)
 -2
 x = -4 +/- √(0)
 -2
 x = -4 +/- 0
 -2
 x = -4 + 0 x = -4 - 0
 -2 -2
 x = -4 x = -4
 -2 -2
 x = 2 x = 2

The solution to the problem is {2, 2}, or {2}. The x - intercept of the problem is (2, 0).

Y - Intercept
f(x) = -x² + 4x - 4
f(x) = -(0)² + 4(0) - 4
f(x) = -(0) + 0 - 4
f(x) = -0 + 0 - 4
f(x) = 0 - 4
f(x) = -4

The y - intercept of the problem is (0, -4).

8 0

3 years ago

If the expression (3^(d)*\sqrt(5))/(3^(2)*\sqrt(45)) is equal to 3, what is the value of d

Digiron [165]

$3^d\cdot\dfrac{\sqrt5}{3^2\cdot\sqrt{45}}=3\\\\\dfrac{3^d\sqrt5}{3^2\sqrt{9\cdot5}}=3\qquad\text{use}\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\\dfrac{3^d\sqrt5}{3^2\sqrt9\cdot\sqrt5}=3\\\\\dfrac{3^d}{3^2\cdot3}=3\qquad\text{use}\ a^n\cdot a^m=a^{n+m}\\\\\dfrac{3^d}{3^{2+1}}=3\\\\\dfrac{3^d}{3^3}=3\qquad\text{multiply both sides by}\ 3^3\\\\3^d=3\cdot3^3\qquad\text{use}\ a^n\cdot a^m=a^{n+m}\\\\3^d=3^{1+3}\\\\3^d=3^4\iff\boxed{d=4}$

8 0

3 years ago

In a jar, there is a green, a blue, and a red marble. You draw (with replacement) a marble from the jar until you get the green

denpristay [2]

Answer:

The value is $P( X = m ) = (\frac{2}{3} )^{m-1 } * \frac{1}{3}$

Step-by-step explanation:

From question we are told that

The number of types of marbles present jar is n = 3

Generally the probability of drawing a green marble is

$P(g) = \frac{1}{3}$

Generally the probability of drawing a marble that is not green is

$P(g') = 1 - \frac{1}{3} = \frac{2}{3}$

From the question we are told that there will be continuous drawing of marbles from the jar (in such a way that after each marble is drawn it is being replaced) until a green marble drawn

Let m be the number of times marbles has been drawn when a green marble was gotten

it then means that for m - 1 times the marbles where drawn a green marble was not obtain.

Generally the probability drawing m times is mathematically is mathematically represented as

$P( X = m ) = (P(g'))^{m-1 } * P(g)$

=> $P( X = m ) = (\frac{2}{3} )^{m-1 } * \frac{1}{3}$

7 0

2 years ago