Answer:
Monkeys have a prehensile tail that allows them to grab and hold onto tree branches - structural
Moose make mating calls to locate potential mates - behavioral
Whales are covered in a thick layer of blubber, insulating their bodies in cold ocean waters - structural
Humans have five toes on each foot to help them maintain balance - structural
Many birds migrate south for the winter in search of food - behavioral
Explanation:
The structural adaptations are adaptations that help the organisms to survive in their environment through development of physical traits that give them an advantage. Such adaptations are the thick layer of blubber of the whales, the five toes of the humans, prehensile tail of the monkeys, rotational toe of the clouded leopard, long of the giraffe etc. The behavioral adaptations are adaptations that help the organisms to survive in their environment, but they manifested through their actions, not their physical traits. Such adaptations are the mating calls of the moos, the migration of the birds in winter, the hibernation of the bears etc.
Mother. red-green color blindedness is maternally inherited
Hormones are a group of chemicals released by exocrine glands

These hormones are directly secreted into bloodstream from where they reach the site.
Nice shift is the change in behavioral or feeding patterns by two or more competing populations to reduce interspecific competition. Interspecific competition is a type of competition between organisms of different species. A niche is a full range of physical and biological conditions in which an organism lives and the way in which the organism uses those conditions.
Answer:
The mentioned parental types are c+m- and c-m+. Thus, the recombinants will be c+m+ and c-m-.
Now, the given distance between c and m is 8 map units. Thus, the recombinant frequency is 8% or 0.08.
The total recombinants from 1000 plaques will come out to be 80,
Thus, the recombinants of each type will be 40.
Total parental type will be 920, and therefore, each parental type count will be 460.
Thus, expected c+m- = 460, expected c-m+ = 460, expected c+m+ = 40 and expected c-m- = 40.