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3 years ago

Find two numbers with the sum of 65.twice the smaller number is ten more than the bigger one

Mathematics

1 answer:

melomori [17]3 years ago

4 0

Step-by-step explanation:

To begin, let’s represent both numbers with letters; x for the smaller number and y for the larger one

The question states that both numbers sum up to 65. With that, we can create our first equation:

x+y = 65

You also went on to say that the smaller number multiplied by 2, is equal to the sum of the larger number and 10. Therefore

2x = y+10

We can rearrange the first equation, place it in the second equation and find our answer. So,

Rearranging equation 1, we have y=65-x. Hence:

2x = 65-x +10

3x = 75

x= 75/3 = 25

Substituting this value into equation 1, we have ‘y’ to be 40 {65–25}

Proof: 2*25 = 50 = 40+10

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{x{ x + 4<0 or 6x>-12)

lora16 [44]

Answer:

$x\in (-\infty , -4) \cup (-2,+\infty)$

Step-by-step explanation:

Solve the system of inequalities:

x + 4 < 0

OR:

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x < -4

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x > -2

The total solution is the disjunction of the individual solutions, i.e., the union of both.

It can be expressed as

$\mathbf{x\in (-\infty , -4) \cup (-2,+\infty)}$

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4 years ago

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Taylor saw an American alligator at a zoo that measured Ask Your Teacher feet long. The record length of an American alligator i

lianna [129]

Answer:

The record alligator is $6\frac{1}{4}$ feet longer than the alligator Taylor saw.

Step-by-step explanation:

Taylor saw an American alligator at a zoo that measured $12\frac{11}{12}$ feet long. The record length of an American alligator is $19\frac{1}{6}$ feet long. How much longer is the record alligator than the alligator Taylor saw?

For this first convert the mixed fraction into an improper fraction.

$12\frac{11}{12}=\frac{155}{12}$

$19\frac{1}{6}=\frac{115}{6}$

Now subtract $\frac{155}{12}$ from $\frac{115}{6}$ .

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Hence, the record alligator is $6\frac{1}{4}$ feet longer than the alligator Taylor saw.

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3 years ago