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irina1246 [14]
4 years ago
13

15 points for the right answer ,,,,!!!!!

Mathematics
1 answer:
Contact [7]4 years ago
5 0
A is true, b is true, but c d aren’t and e is
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In ΔVWX, {VX} is extended through point X to point Y, m∠VWX = (3x+2)) ∘ , m∠WXY = (6x-19)∘ , and m∠XVW = (x+17)^{\circ}(x+17) ∘
blagie [28]

Answer:

∠XVW = 36°

Step-by-step explanation:

The external angle of a triangle is equal to the sum of the 2 opposite interior angles.

∠WXY is an external angle to the triangle and

∠XVW and ∠VWX are the 2 opposite interior angles, thus

6x - 19 = x + 17 + 3x + 2, that is

6x - 19 = 4x + 19 ( subtract 4x from both sides )

2x - 19 = 19 ( add 19 to both sides )

2x = 38 ( divide both sides by 2 )

x = 19

Hence

∠XVW = x + 17 = 19 + 17 = 36°

4 0
3 years ago
Hi what is a+3squared /56
Scrat [10]

Answer:

well friend you answer is

Step-by-step explanation:

a+ 3/56

i hope this helped

5 0
2 years ago
Read 2 more answers
Consider the function on the interval (0, 2π). f(x) = 7 sin2(x) + 7 sin(x) (a) Find the open interval(s) on which the function i
-BARSIC- [3]

Answer with Step-by-step explanation:

Given

f(x)=7sin(2x)+7sin(x)

Differentiating both sides by 'x' we get

14cos(2x)+7cos(x)=f'(x)

Now we know that for an increasing function we have

f'(x)>0\\\\14cos(2x)+7cos(x)>0\\\\2cos(2x)+cos(x)>0\\\\2(2cos^{2}(x)-1)+cos(x)>0\\\\4cos^{2}(x)+cos(x)-2>0\\\\(2cos(x)+\frac{1}{2})^2-2-\frac{1}{4}>0\\\\(2cos(x)+\frac{1}{2})^2>\frac{9}{4}\\\\2cos(x)>\frac{3}{2}-\frac{1}{2}\\\\\therefore cos(x)>\frac{1}{4}\\\\\therefore x=[0,cos^{-1}(1/4)]\cup [2\pi-cos^{-1}(1/4),2\pi ]

Similarly for decreasing function we have

[tex]f'(x)

Part b)

To find the extreme points we equate the derivative with 0

f'(x)=0\\\\cos(x)=\frac{1}{4}\\\\x=cos^{-1}(\frac{1}{4})

Thus point of extrema is only 1.

4 0
4 years ago
Answer question from picture.
Anna007 [38]

The limit (as 'x' approaches zero) of    x²/(2x+1)  is 

             0 / (0+1)  =  0 .

You get this by substituting the limit in place of 'x'.

Sometimes that doesn't work.  Sometimes it gives you
monstrosities like   0/0,   or   1/0,   or   ∞/∞ .

But it works for this one.  There's nothing wrong with  0/1  =  zero .
4 0
4 years ago
Place in descending order:<br> 0.035,0.53,0.05,0.305
Sveta_85 [38]

Answer:

Step-by-step explanation:

0.305 = 305/1000

0.05 = 50/1000

0.53 = 530/1000

0.035= 35/1000

descending orde ris ;           0.53  ; 0.305 ; 0.05 ; 0.035

3 0
3 years ago
Read 2 more answers
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