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2 years ago

2(r+5)-4(r-1)=32 what is the solution?

Mathematics

2 answers:

muminat2 years ago

7 0

Answer:

2r+10-4r+4=32

-2r+14=32

-2r= 32-14

-2r=18

R= -9

Step-by-step explanation:

DanielleElmas [232]2 years ago

7 0

Answer:

r=-9

Step by step explanation:

2(r+5)-4(r-1)=32

Distribute 2 through the parentheses

2r+10-4(r-1)=32

Distribute -4 through the parentheses

2r+10-4r+4=32

Collect like terms

-2r+10+4=32

Add the numbers

-2r+14=32

Move the constant to the right-hand side and change its sign

-2r=32-14

Subtract the numbers

-2r=18

Divide both sides of the equation by -2

r=-9

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