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Nitella [24]
3 years ago
9

D

Mathematics
1 answer:
Lera25 [3.4K]3 years ago
6 0

First find function

\\ \bull\tt\dashrightarrow f(x)=2(x+3)-3

\\ \bull\tt\dashrightarrow f(x)=2x+6-3

\\ \bull\tt\dashrightarrow f(x)=2x+3

Now

\\ \bull\tt\dashrightarrow y=2x+3

\\ \bull\tt\dashrightarrow x=\dfrac{y-3}{2}

But

\\ \bull\tt\dashrightarrow y=f(x)

\\ \bull\tt\dashrightarrow x=f^{-1}(y)

Hence

.

\\ \bull\tt\dashrightarrow f^{-1}y=\dfrac{y-3}{2}

Replace y by x

\\ \bull\tt\dashrightarrow f^{-1}(x)=\dfrac{x-3}{2}

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