The third angle is obtuse.
Since the shape has 3 sides, then the total measure of degrees is (n-2)180 = (3-2)180 = 180°.
So our equation would be
180° = 35° + 30° + x°
x = 115°
115 is greater than 90, so the angle is obtuse.
18. 105=2x-11 so 105+105=210 and all four angels equal 360 so 360-210=150 so 150/2=75
19. 6x+19+x =180
X=23
So AEB:75 BEC:123 CED:75 AED:23
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Answer:
Step-by-step explanation:
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Answer:
See the attached figure which represents the problem.
As shown, AA₁ and BB₁ are the altitudes in acute △ABC.
△AA₁C is a right triangle at A₁
So, Cos x = adjacent/hypotenuse = A₁C/AC ⇒(1)
△BB₁C is a right triangle at B₁
So, Cos x = adjacent/hypotenuse = B₁C/BC ⇒(2)
From (1) and (2)
∴ A₁C/AC = B₁C/BC
using scissors method
∴ A₁C · BC = B₁C · AC
It's C. In order to be in standard form you have to have all your exponents in descending order. They don't all have to be there in order, the ones that are just have to go from highest to lowest.
