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kow [346]
3 years ago
13

In which situation do the quantities combine to make 0?

Mathematics
2 answers:
Natasha2012 [34]3 years ago
6 0

The answer is A

Step-by-step explanation:

If dylan borrows $10 from his friend, then pays it back, he is going to be left back at the quantity 0

The other ones dont match the quantity 0

Rus_ich [418]3 years ago
3 0

Answer:

A. Dylan borrows $10 from a friend on Friday. He pays his friend back $10 on Saturday is the correct answer

Step-by-step explanation:

Because, if Dyan will borrow $10 from friend and pays back. So for answer we just need subtract $10 from $10. That is equal to 0

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4−(3x−8)=21 solve this pls​
riadik2000 [5.3K]

Answer:

4 - ( 3x - 8 ) = 21

break the bracket first ,it gives : 4 - 3x + 8 = 21

12 - 3x = 21

- 3x = 21 - 12

- 3x = 9

-x = 9/3

-x = 3

X = - 3

[ check if the answer is correct, put -3 instead of X in the above equation ! we get 4 - { 3(-3) - 8 } = 21

4 - { - 9 - 8 } = 21

4 - { - 17 } = 21

break the bracket, minus and minus will multiply and will become plus , so we have 4 + 17 = 21 , hence 21 = 21 ! therefore X = -3

5 0
3 years ago
Maria is recording the percentages she earned on each quiz in her math class. Here are her results for the last 7 quizzes.
Paha777 [63]
22 because you take the smallest and largest number and subtract them so you do 81-59=22
4 0
3 years ago
Law of sines: How many distinct triangles can be formed for which m∠A = 75°, a = 2, and b = 3? No triangles can be formed. One t
Vinvika [58]

We have been given angle A as 75 degrees and sides a = 2 and b = 3.

Using Sine rule, we can set up:

\frac{Sin(A)}{a}=\frac{Sin(B)}{b}

Upon substituting the given values of angle A, and sides a and b, we get:

\frac{Sin(75)}{2}=\frac{Sin(B)}{3}

Upon solving this equation for B, we get:

\Rightarrow 3Sin(75)=2Sin(B)\\  \Rightarrow Sin(B)=\frac{3Sin(75)}{2}\\  \Rightarrow Sin(B)=1.4488\\

Since we know that value of Sine cannot be more than 1. Hence there are no values possible for B.

Hence, the triangle is not possible. Therefore, first choice is correct.

7 0
3 years ago
Read 2 more answers
What does x equal in: 5x-2+x=9+3x+10
TiliK225 [7]
5x-2+x=9+3x+10

therefore, x = 7
6 0
4 years ago
9. A large electronic office product contains 2000 electronic components. Assume that the probability that each component operat
Marysya12 [62]

Answer:

97.10% probability that five or more of the original 2000 components fail during the useful life of the product.

Step-by-step explanation:

For each component, there are only two possible outcomes. Either it works correctly, or it does not. The probability of a component falling is independent from other components. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

n = 2000, p = 1-0.995 = 0.005

Approximate the probability that five or more of the original 2000 components fail during the useful life of the product.

We know that either less than five compoenents fail, or at least five do. The sum of the probabilities of these events is decimal 1. So

P(X < 5) + P(X \geq 5) = 1

We want P(X \geq 5)

So

P(X \geq 5) = 1 - P(X < 5)

In which

P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{2000,0}.(0.005)^{0}.(0.995)^{2000} = 0.000044

P(X = 1) = C_{2000,1}.(0.005)^{1}.(0.995)^{1999} = 0.000445

P(X = 2) = C_{2000,2}.(0.005)^{2}.(0.995)^{1998} = 0.002235

P(X = 3) = C_{2000,3}.(0.005)^{3}.(0.995)^{1997} = 0.007480

P(X = 4) = C_{2000,4}.(0.005)^{4}.(0.995)^{1996} = 0.018765

P(X < 5) = P(X = 0) + `P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.000044 + 0.000445 + 0.002235 + 0.007480 + 0.018765 = 0.0290

P(X \geq 5) = 1 - P(X < 5) = 1 - 0.0290 = 0.9710

97.10% probability that five or more of the original 2000 components fail during the useful life of the product.

4 0
3 years ago
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