15q – 4r = 62<br> 5q + 8r = 86

What does a decimal between two fractions mean

Anni [7]

Answer:

Multiplication

Step-by-step explanation:

I think what you're talking about is not a decimal, but a multiplication point:

$\frac{1}{2} \: . \: \frac{3}{4}$

This dot can donate multiplication when in the middle of two numbers and/or fractions.

But if you're talking about some other point, then I don't know, sorry. :(

6 0

3 years ago

Read 2 more answers

E = {10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23}

Nata [24]

Answer:

A=11,13,17,19 B=12,18 None=10,14,16,19 Both=15

Step-by-step explanation:

11,13,15,17,19 are all odd so they go in A

12,15,18 Are all multiples of 3 so they go in B

10,14,16,19 Are not classified so they go outside of the diagram but inside E

15 is odd and a multiple of 3 so put it in the center and not with A and B

6 0

3 years ago

Which is the equation of the line that passes through the points (-4, 8) and (1, 3)?

SVETLANKA909090 [29]

Answer:

Can l get sum more deatal

Step-by-step explanation:

4 0

3 years ago

All the seats in the theater are divided into 6 groups. There are 35 seats in each group. Using the variable s, write and solve

olga_2 [115]

The answers should be 210

3 0

3 years ago

The U.S. Department of Transportation, National Highway Traffic Safety Administration, reported that 77% of all fatally injured

FrozenT [24]

Answer:

The p value obtained was a low value and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of of driver fatalities related to alcohol is less from 0.77 or 77%.

Step-by-step explanation:

1) Data given and notation n

n=53 represent the random sample taken

X=35 represent the automobile driver fatalities in a certain county involved with an intoxicated driver

$\hat p=\frac{35}{53}=0.660$ estimated proportion of automobile driver fatalities in a certain county involved with an intoxicated driver

$p_o=0.77$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the population proportion of driver fatalities related to alcohol is less than 77% or 0.77 in Kit Carson:

Null hypothesis: $p\geq 0.77$

Alternative hypothesis: $p < 0.77$

When we conduct a proportion test we need to use the z statisitc, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.660 -0.77}{\sqrt{\frac{0.77(1-0.77)}{53}}}=-1.903$

4) Statistical decision

It's important to refresh the p value method or p value approach . "This methos is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is an unilateral lower test the p value would be:

$p_v =P(z$

So the p value obtained was a low value and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of of driver fatalities related to alcohol is less from 0.77 or 77%.

8 0

3 years ago

15q – 4r = 62 5q + 8r = 86