√8
for the equations of circles: x²+y²= (radius)²
Perimeter = Sum of three sides.
Let the third side be = t
Perimeter = 8x + 3y
8x + 3y = (4x + y) + (2x - 3y) + t
8x + 3y = 4x + y + 2x - 3y + t
8x + 3y = 4x +2x + y - 3y + t
8x + 3y = 6x - 2y + t
8x - 6x + 3y + 2y = t
2x + 5y = t.
Therefore third side = 2x + 5y
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What is the common multiplier in the proportion 4072-01-01-05-00_files/i0370000.jpg?
^^^^^That's all this we can see, there's no link.
Okay so for consecutive
Your first integer can be represented by the variable x.
The second number will be x+1, since it is consecutive. (For example 1+1=2, where 1 and 2 are consecutive)
So, your equation will be
x+(x+1)=-35
Combine like terms
2x+1=-35
-1 -1
—————
2x=-36
Begin isolating the variable by moving the 1 to the right
Divide each side by 2 to completely isolate x
2x=-36
—— —-
2 2
x=-18
So, one of the numbers is -18. For the other integer, insert -18.
x+1=-18+1
-17
So one integer is -17, and the other is -18. You can check by adding these integers, which gives you -35.
Hope this helps!!